Sign Tracker Log
IEP Progress Monitoring System
Sign Tracker Log
Teacher Resource
Student Name:
IEP Goal Code:
Implementation Team:
Target Completion:
Focus IEP Objective (CCSS 7.NS.A.2.A)
By the end of the instructional period, given a 5-question weekly probe on signed integer multiplication and operational properties (such as distributive rules and justifying why \((-1)(-1)=1\)), the student will solve mathematical and contextual problems with at least accuracy on 3 out of 4 consecutive probes.
Baseline & Weekly Probe Scores
| Interval | Date Given | Score (/5) | Percentage | Observed Strategy / Errors |
|---|
| Baseline | | /5 | % | Initial baseline check... |
| Probe A (Wk 1) | | /5 | % | |
| Probe B (Wk 2) | | /5 | % | |
| Probe C (Wk 3) | | /5 | % | |
| Probe D (Wk 4) | | /5 | % | |
Visual Progress Graph
Plot points and connect with a trend line to demonstrate progress.
5 (100%) 4 (80%) 3 (60%) 2 (40%) 1 (20%) 0 (0%)
Base
Probe A
Probe B
Probe C
Probe D
IEP Accommodations
Check those utilized during assessment:
Extra Time (e.g., untimed/1.5x) Frequent Breaks Read Aloud (for word problems) Visual Anchor Chart (no answers) Reduced Distractions / Small Group
Administration Guidelines
Standard Execution: Administer one probe per week under stable conditions. Probes are designed to take 5-10 minutes. Read directions and word problems aloud if needed for language/reading accommodations.
Conceptual Assessment: Each probe evaluates both procedural computation (Questions 1, 2, 5) and critical property conceptualization (Questions 3, 4). Correct answers require both calculation and complete property justification.
Sign Power Probes
IEP Progress Probe
Signed Operations: Probe A
Week 1
Student Name:
Date:
Score / Progress:
_____ / 5
Directions: Solve each of the 5 problems below. Show your mathematical work in the space provided. Write your final answer clearly.
Q1. Procedural Computation (2 Integers) 1 Point
Compute the product:
\( (-7) \times 8 \)
Final Answer:
Q2. Procedural Computation (3 Integers) 1 Point
Compute the product:
\( (-3) \times (-2) \times (-5) \)
Final Answer:
Q3. Properties of Operations (Distributive Property) 1 Point
Apply the distributive property to expand and compute the expression:
\( -4 \times [10 + (-2)] \)
Expanded Form: _________________ Final Value:
Q4. Conceptual Justification (Negative Proof) 1 Point
Complete the proof establishing why \( (-1) \times (-1) = 1 \):
Step 1: \( (-1) \times [1 + (-1)] = (-1) \times 0 = 0 \)
Step 2: \( [(-1) \times 1] + [(-1) \times (-1)] = 0 \) (by Distributive Property)
Step 3: \( -1 + [(-1) \times (-1)] = 0 \)
Based on Step 3, explain why \( (-1) \times (-1) \) must equal \( 1 \):
Q5. Real-World Context (Signed Word Problem) 1 Point
A scientific research submersible descends at a rate of 6 meters per second. Represent this rate as a signed integer, write an expression, and compute the submersible's total depth change after 8 seconds.
Expression: _________________ Answer with units:
IEP Progress Probe
Signed Operations: Probe B
Week 2
Student Name:
Date:
Score / Progress:
_____ / 5
Directions: Solve each of the 5 problems below. Show your mathematical work in the space provided. Write your final answer clearly.
Q1. Procedural Computation (2 Integers) 1 Point
Compute the product:
\( 9 \times (-6) \)
Final Answer:
Q2. Procedural Computation (3 Integers / Exponents) 1 Point
Compute the product:
\( (-2)^{2} \times (-4) \)
Final Answer:
Q3. Properties of Operations (Distributive Property) 1 Point
Apply the distributive property to expand and compute the expression:
\( -3 \times [(-5) + 9] \)
Expanded Form: _________________ Final Value:
Q4. Conceptual Justification (Negative Proof) 1 Point
Explain how the Distributive Property proves why \( (-1) \times (-1) = 1 \):
Hint: If we expand \( (-1) \times [1 + (-1)] = 0 \), we get \( (-1 \times 1) + (-1 \times -1) = 0 \).
Q5. Real-World Context (Signed Word Problem) 1 Point
The temperature in Fairbanks, Alaska is dropping at a rate of \( 4^\circ \text{F} \) per hour. Represent this drop as a negative rate, write an expression, and compute the total change in temperature after 6 hours.
Expression: _________________ Answer with units:
IEP Progress Probe
Signed Operations: Probe C
Week 3
Student Name:
Date:
Score / Progress:
_____ / 5
Directions: Solve each of the 5 problems below. Show your mathematical work in the space provided. Write your final answer clearly.
Q1. Procedural Computation (2 Integers) 1 Point
Compute the product:
\( (-12) \times (-5) \)
Final Answer:
Q2. Procedural Computation (3 Integers) 1 Point
Compute the product:
\( (-1) \times (-8) \times (-3) \)
Final Answer:
Q3. Properties of Operations (Distributive Property) 1 Point
Apply the distributive property to expand and compute the expression:
\( -5 \times [8 + (-3)] \)
Expanded Form: _________________ Final Value:
Q4. Conceptual Justification (Vocabulary & Definition) 1 Point
Complete the sentences using the words opposite, distributive, or zero:
1. Multiplying \( (-1) \times [1 + (-1)] \) equals ________ because any number times zero is zero.
2. Proving that \( (-1)(-1) \) is the ____________ of \( -1 \) shows why negative times negative is positive.
Q5. Real-World Context (Signed Word Problem) 1 Point
A mining excavation company descends 12 meters underground every day. Represent this daily change as a signed integer, write an expression, and compute the total depth change of the excavation after 5 days.
Expression: _________________ Answer with units:
IEP Progress Probe
Signed Operations: Probe D
Week 4
Student Name:
Date:
Score / Progress:
_____ / 5
Directions: Solve each of the 5 problems below. Show your mathematical work in the space provided. Write your final answer clearly.
Q1. Procedural Computation (2 Integers) 1 Point
Compute the product:
\( 8 \times (-11) \)
Final Answer:
Q2. Procedural Computation (3 Integers) 1 Point
Compute the product:
\( (-5) \times (-4) \times (-2) \)
Final Answer:
Q3. Properties of Operations (Distributive Property) 1 Point
Apply the distributive property to expand and compute the expression:
\( -2 \times [(-7) + (-3)] \)
Expanded Form: _________________ Final Value:
Q4. Conceptual Justification (Proof Complete) 1 Point
Fill in the blank to complete the logic of the multiplication sign proof:
"If the distributive property is true, then \( (-1) \times [1 + (-1)] \) expands to \( (-1)(1) + (-1)(-1) \). We know that \( 1 + (-1) = 0 \), so the expanded equation must equal 0. Since \( (-1)(1) = -1 \), we write \( -1 + [(-1)(-1)] = 0 \). This means \( (-1)(-1) \) must be the number ___________."
Q5. Real-World Context (Signed Word Problem) 1 Point
An online savings account charges a recurring monthly maintenance fee of \( \$8 \). Represent this monthly charge as a signed integer, write an expression, and compute the total change in the account balance due to these fees after 7 months.
Expression: _________________ Answer with units:
Sign Power Keys
IEP Progress Monitoring System
Answer Key & Teacher Guide
Probes A & B
Grading Standards:
Award 1 point per question. For procedural questions (Q1, Q2), award full credit for the correct sign and value. For property questions (Q3, Q4, Q5), award full credit only if the steps/explanations demonstrate appropriate application of the property or context.
Probe A Answers (Week 1)
Q1 Answer: -56
Explanation: A negative multiplied by a positive always yields a negative. \( 7 \times 8 = 56 \), so \( (-7) \times 8 = -56 \).
Q2 Answer: -30
Explanation: Multiply in order. \( (-3) \times (-2) = 6 \). Then multiply by the third: \( 6 \times (-5) = -30 \). An odd number of negative factors yields a negative product.
Q3 Answer: Expanded: (-4 \times 10) + (-4 \times -2) | Final Value: -32
Explanation: Distribute the \( -4 \) over both values. \( -40 + 8 = -32 \).
Q4 Answer: 1 (or equivalent explanation)
Explanation: Since \( -1 + [(-1) \times (-1)] = 0 \), then by definition of additive inverse, \( (-1) \times (-1) \) must be the opposite of \( -1 \), which is \( 1 \).
Q5 Answer: Expression: -6 \times 8 | Final Answer: -48 meters (or a depth of 48 meters)
Explanation: Descent rate is represented as \( -6 \). Over 8 seconds, \( -6 \times 8 = -48 \).
Probe B Answers (Week 2)
Q1 Answer: -54
Explanation: A positive times a negative yields a negative. \( 9 \times (-6) = -54 \).
Q2 Answer: -16
Explanation: Compute exponent first: \( (-2)^2 = (-2) \times (-2) = 4 \). Next: \( 4 \times (-4) = -16 \).
Q3 Answer: Expanded: (-3 \times -5) + (-3 \times 9) | Final Value: -12
Explanation: Distribute the \( -3 \). \( 15 + (-27) = -12 \).
Q4 Answer: Explains that the sum must be zero, forcing \( (-1) \times (-1) = 1 \)
Explanation: Expanding \( (-1) \times [1 + (-1)] = 0 \) yields \( -1 + [(-1) \times (-1)] = 0 \). The only number added to \( -1 \) to equal \( 0 \) is its opposite, which is \( 1 \).
Q5 Answer: Expression: -4 \times 6 | Final Answer: -24°F (or a decrease of 24°F)
Explanation: The temperature drop is a rate of \( -4 \) per hour. Over 6 hours, \( -4 \times 6 = -24 \).
IEP Progress Monitoring System
Answer Key & Teacher Guide
Probes C & D
