D. No; Flask 1 shows that yeast generates gas without sugar.
Target Skill: Cross-Referencing Tabular Data Against Claims SAT / ACT Science Warm-Up Series
DAY 04 • ECOLOGY
Warm-Up Drill • 3 Minutes
Yr 0 Yr 5 Yr 10 Yr 15 Yr 20 Time (Years) Population Density — Snowshoe Hare (Prey) -- Canadian Lynx (Predator)
Based on the curves, what is the most direct cause of the decline in snowshoe hare population following Year 5?
A. Lynx density peaked right after the hare peak, driving predation.
B. Hare populations fell because lynx counts reached an all-time low.
C. Hare birth rates declined strictly due to 20-year weather cycles.
D. Predators peak three years prior to their prey species.
Target Skill: Analyzing Phase Lag in Coupled Oscillations SAT / ACT Science Warm-Up Series
DAY 05 • MICROBIOLOGY
Warm-Up Drill • 3 Minutes
0 15 30 Zone Diam. (mm) Amp Cipro Tet Vanc E. coli (Gram -) S. aureus (Gram +)
Larger inhibition zones indicate greater susceptibility. Which antibiotic is potent against S. aureus but completely ineffective against E. coli?
A. Ampicillin
B. Ciprofloxacin
C. Tetracycline
D. Vancomycin
Target Skill: Comparing Grouped Clustered Bar Graphs SAT / ACT Science Warm-Up Series
DAY 06 • PHYSICAL CHEMISTRY
Warm-Up Drill • 3 Minutes
0 10 20 30 40 Volume (L) 0 2 4 Pressure (atm)
An ideal gas is held at 298 K in a piston. When the chamber volume expands from 10 L to 40 L, what occurs to the gas pressure?
A. It quadruples because volume and pressure are directly proportional.
B. It decreases to one-fourth of its initial value.
C. It falls linearly to exactly 0 atm.
D. It remains unchanged because temperature is held fixed.
Target Skill: Identifying Inverse Proportionality & Hyperbolic Curves SAT / ACT Science Warm-Up Series
DAY 07 • CHEMICAL KINETICS
Warm-Up Drill • 3 Minutes
0 20 40 60 Time (seconds) 0.0 0.5 1.0 [Concentration] (M) Product B Reactant A
For \(A \rightarrow B\), how does the rate of formation of Product B between 0–20 s compare to between 40–60 s?
A. Faster during 0–20 s because reactant concentration is greatest.
B. Faster during 40–60 s as equilibrium approaches.
C. Constant across the entire duration.
D. Zero between 0–20 s due to activation lag.
Target Skill: Analyzing Rate as Curve Tangent Slope SAT / ACT Science Warm-Up Series
DAY 08 • ANALYTICAL CHEMISTRY
Warm-Up Drill • 3 Minutes
0 15 25 35 50 0.10 M NaOH Added (mL) 1 7 13 Solution pH
A 25.0 mL unknown HCl aliquot is titrated with 0.10 M NaOH. What is the equivalence point volume and resulting pH?
A. 15.0 mL NaOH; pH = 3.2
B. 25.0 mL NaOH; pH = 7.0
C. 35.0 mL NaOH; pH = 11.8
D. 50.0 mL NaOH; pH = 13.0
Target Skill: Reading Sigmoidal Inflection Points SAT / ACT Science Warm-Up Series
DAY 09 • SOLUTION CHEMISTRY
Warm-Up Drill • 3 Minutes
0 20 40 60 80 Temperature (°C) 0 50 100 g Solute / 100g H₂O KNO₃ NaCl Ce₂(SO₄)₃
At 60°C, a solution contains 70 g of KNO₃ dissolved in 100 g H₂O. Based on the graph, how is this mixture classified?
A. Saturated, because it lies directly on the boundary.
B. Unsaturated, because the saturation threshold at 60°C is ~105 g.
C. Supersaturated, because precipitate must form instantly.
D. Insoluble, because KNO₃ decomposes above 40°C.
Target Skill: Multiline Phase Boundary Classification SAT / ACT Science Warm-Up Series
DAY 10 • THERMODYNAMICS
Warm-Up Drill • 3 Minutes
0 5 15 25 35 Heat Added (kJ) -20 0 100 Temperature (°C) Melting Plateau Boiling Plateau
During the boiling plateau (100°C), thermal heat is continuously added, yet temperature remains constant. What explains this?
A. Heat breaks intermolecular bonds rather than increasing kinetic energy.
B. Specific heat capacity falls to zero during vaporization.
C. Water molecules split into hydrogen and oxygen gases.
D. Sensors cannot record temperatures past 100°C.
Target Skill: Latent Heat vs. Sensible Heat Plateaus SAT / ACT Science Warm-Up Series
DAY 11 • ATMOSPHERIC SCIENCE
Warm-Up Drill • 3 Minutes
-80 -40 0 40 Temperature (°C) 0 12 50 85 Altitude (km) Troposphere Stratosphere Mesosphere
In which layer does temperature increase as altitude increases, and what mechanism is responsible?
A. Troposphere; heat radiating from Earth's terrestrial crust.
B. Stratosphere; UV radiation absorption by the ozone layer.
C. Mesosphere; ionization of inert noble gases.
D. All layers show strict temperature reduction with altitude.
Target Skill: Analyzing Inverted Layered Gradients SAT / ACT Science Warm-Up Series
DAY 12 • GEOPHYSICS
Warm-Up Drill • 3 Minutes
0 2,000 4,000 6,000 8,000 Distance to Epicenter (km) 0 10 20 Travel Time (min) P-wave S-wave
A seismograph records the first P-wave arrival at 10:00 AM and S-wave at 10:07 AM (7-minute lag). How far is the epicenter?
A. Approximately 1,500 km
B. Approximately 5,000 km
C. Approximately 8,000 km
D. Cannot be determined without wave amplitude data.
Target Skill: Calculating Distance from Wave Time-Gap Difference SAT / ACT Science Warm-Up Series
DAY 13 • OCEANOGRAPHY
Warm-Up Drill • 3 Minutes
1980 1995 2010 2025 330 420 Atm CO₂ (ppm) 8.05 8.15 Ocean pH
Based on the long-term oceanic monitoring station data, which statement accurately summarizes the relationship between atmospheric CO₂ and ocean pH?
A. Directly proportional; rising CO₂ increases seawater alkalinity.
B. Inversely related; as CO₂ levels rise, ocean pH steadily drops.
C. Uncorrelated; ocean chemistry remains completely buffered.
D. Cyclical; pH peaks identically every 10 years.
Target Skill: Dual Independent Y-Axis Correlation SAT / ACT Science Warm-Up Series
DAY 14 • ASTROPHYSICS
Warm-Up Drill • 3 Minutes
30,000K 10,000K 5,500K 3,000K Surface Temperature (K) 10⁻⁴ 1 10⁴ Luminosity (L☉) Main Sequence Sun (1 L☉) Giants White Dwarfs
Along the Main Sequence of the H-R diagram, what characteristic is shared by stars with the highest luminosity?
A. Low surface temperatures that radiate deep red light.
B. Highest surface temperatures that radiate blue-white light.
C. Longest lifespans due to slow internal fuel consumption.
D. Identical luminosity output to white dwarfs.
Target Skill: Reversed Horizontal Scale & Logarithmic Axes SAT / ACT Science Warm-Up Series
DAY 15 • HYDROLOGY
Warm-Up Drill • 3 Minutes
Jan Mar May Jul Sep Nov Rainfall Water Table Height
Heavy precipitation peaks in May, but the groundwater table elevation does not peak until July. What hydrological process causes this delay?
A. Surface runoff completely evaporates before reaching the soil.
B. Water percolation through porous soil and rock requires transit time.
C. Aquifers lose all permeability during rainy seasons.
D. Plant transpiration reaches its annual maximum in winter.
Target Skill: Physical Interpretation of Time-Shifted Trends SAT / ACT Science Warm-Up Series
DAY 16 • EXPERIMENTAL DESIGN
Warm-Up Drill • 3 Minutes
| Group | Nitrogen (mM) | Phosphorus (mM) | Biomass (g) |
|---|---|---|---|
| Control | 10.0 | 2.0 | 45.2 g |
| Trial 1 | 2.0 | 2.0 | 18.4 g |
| Trial 2 | 10.0 | 0.4 | 32.1 g |
| Trial 3 | 2.0 | 0.4 | 14.1 g |
Controlled constants: Light (16h/d), Water pH (6.2), Temperature (22°C).
To isolate the specific effect of nitrogen deficiency while keeping phosphorus constant, which pair of groups must be compared?
A. Control and Trial 1
B. Trial 1 and Trial 2
C. Control and Trial 3
D. Trial 2 and Trial 3
Target Skill: Controlled Variable Isolation in Multi-Factor Trials SAT / ACT Science Warm-Up Series
DAY 17 • CONFLICTING HYPOTHESES
Warm-Up Drill • 3 Minutes
0 5 10 15 20 Distance from Galactic Center (kpc) 0 150 300 Orbital Velocity (km/s) Observed Rotation Predicted by Luminous Mass
Scientist 1 posits dark matter halos, while Scientist 2 modifies gravity. What primary observational evidence motivates both models?
A. Orbital speeds remain flat at outer radii instead of declining.
B. Orbital velocity falls to zero beyond 10 kpc from the center.
C. Inner core stars travel far faster than Keplerian predictions.
D. Visible starlight mass accurately matches all observed velocities.
Target Skill: Evaluating Contending Hypotheses Against Anomalous Data SAT / ACT Science Warm-Up Series
DAY 18 • BIOSTATISTICS
Warm-Up Drill • 3 Minutes
0 50 100 Mean Response (%) Drug A Drug B Drug C
Error bars show ±1 standard deviation. Which pair does NOT show a statistically distinct difference based on error bar overlap?
A. Drug A and Drug B, because their error bars overlap widely.
B. Drug B and Drug C, because both have means over 60%.
C. Drug A and Drug C, because standard deviations are identical.
D. All three drugs demonstrate distinct, non-overlapping efficacy.
Target Skill: Interpreting Error Bars & Statistical Uncertainty SAT / ACT Science Warm-Up Series
DAY 19 • CLASSICAL MECHANICS
Warm-Up Drill • 3 Minutes
-A (Left Max) 0 (Center) +A (Right Max) Displacement from Center 0 E / 2 E_total Total Mechanical Energy Kinetic (KE) Potential (PE)
As a frictionless pendulum swings through equilibrium (displacement = 0), what is the relationship between KE and PE?
A. KE is at its absolute maximum while PE is zero.
B. PE is at its maximum while KE drops to zero.
C. Both KE and PE equal exactly 50% of total energy.
D. Total mechanical energy temporarily drops to zero.
Target Skill: Energy Conservation & Dynamic Transformations SAT / ACT Science Warm-Up Series
DAY 20 • CLIMATE SCIENCE
Warm-Up Drill • 3 Minutes
2005 2010 2015 2020 2025 0 Gt -1,500 -3,000 Ice Mass Change (Gt) 2020: -2,250 Gt
From 2005 to 2020, ice sheets lost an average of ~150 Gt/year. If this constant rate continues through 2025, what will the cumulative loss reach?
A. -1,500 Gigatons
B. -2,250 Gigatons
C. -3,000 Gigatons
D. -4,500 Gigatons
Target Skill: Linear Slope Calculation & Value Extrapolation SAT / ACT Science Warm-Up Series
Teacher Tip: Remind students to always verify axis units and legends before reading values. Page 1 of 4
Teacher Reference & Answer Key
Days 06–10 Explanations
ACT Science: Research Summaries
DAY 06 Boyle's Law: Pressure vs. Volume
CORRECT: B
Rationale: Boyle's Law states \(P_1 V_1 = P_2 V_2\). At \(V = 10\) L, \(P = 4.0\) atm (\(P \cdot V = 40\)). When volume expands 4-fold to 40 L, pressure drops to \(40 / 40 = 1.0\) atm, which is exactly \(1/4\) of the initial value.
Distractor Analysis: Choice A confuses direct and inverse proportionality. Choice C mistakes asymptotic hyperbolic decay for a linear intercept. Choice D forgets that pressure changes when volume changes at constant T.
DAY 07 Reaction Kinetics: Reactants vs. Products
CORRECT: A
Rationale: Reaction rate corresponds to the slope of concentration vs. time (\(\Delta [B] / \Delta t\)). Between 0–20 s, [B] climbs steeply from 0.0 M to 0.6 M (slope \(\approx 0.03\) M/s). Between 40–60 s, the curve flattens (slope \(\approx 0.003\) M/s).
Distractor Analysis: Choice B confuses cumulative product amount with rate of production. Choice C ignores the pronounced curvature. Choice D falsely posits an induction period absent from the graph.
DAY 08 Acid-Base Titration Curve
CORRECT: B
Rationale: The equivalence point of a strong acid titrated by a strong base is marked by the midpoint of the vertical sigmoid jump, which aligns precisely at 25.0 mL of NaOH titrant and pH = 7.0 (neutral salt NaCl).
Distractor Analysis: Choice A reflects an early buffer region prior to equivalence. Choice C is well past the equivalence point. Choice D represents excess hydroxide asymptotic leveling.
DAY 09 Solubility Curves of Inorganic Salts
CORRECT: B
Rationale: Locate 60°C on the x-axis and trace vertically to the KNO₃ curve: the saturation boundary is at ~105 g solute / 100 g H₂O. Because 70 g lies below this curve, the solution is unsaturated and can dissolve ~35 g more KNO₃.
Distractor Analysis: Choice A would only be correct if exactly 105 g were dissolved. Choice C would require dissolving >105 g without precipitate. Choice D contradicts the high solubility shown.
DAY 10 Heating Curve of Water
CORRECT: A
Rationale: During a phase change plateau, added heat goes into latent heat of vaporization (\(\Delta H_{vap}\)), breaking intermolecular hydrogen bonds between liquid molecules to create gas, without increasing average molecular kinetic energy (temperature).
Distractor Analysis: Choice B misstates specific heat fundamentals. Choice C describes chemical decomposition (electrolysis), not physical boiling. Choice D is an absurdity trap.
Teacher Tip: Highlight the difference between slope (rate) and position (amount) in kinetic graphs. Page 2 of 4
Teacher Reference & Answer Key
Days 11–15 Explanations
ACT Science: Data Representation
DAY 11 Atmospheric Temperature Inversions
CORRECT: B
Rationale: In the stratosphere (12–50 km altitude), the temperature profile shifts from -55°C at the tropopause up to 0°C at the stratopause. This inversion is generated by the absorption of solar ultraviolet photons by ozone (\(O_3\)).
Distractor Analysis: Choice A incorrectly claims temperature increases with altitude in the troposphere (it cools with altitude). Choice C incorrectly identifies the mesosphere, which cools to -85°C. Choice D ignores the graph's zig-zag trend.
DAY 12 Seismic P-Wave & S-Wave Travel Times
CORRECT: B
Rationale: Find the distance where the vertical gap between the S-wave curve and P-wave curve equals 7 minutes. At 5,000 km, P-wave travel time is ~8.5 min and S-wave travel time is ~15.5 min (\(15.5 - 8.5 = 7.0\) min).
Distractor Analysis: At 1,500 km, the gap is only ~2.5 minutes. At 8,000 km, the gap exceeds 10 minutes. Choice D ignores the standard seismological distance-finding method.
DAY 13 Ocean Acidification: CO₂ vs. pH
CORRECT: B
Rationale: The left axis shows atmospheric CO₂ rising from 335 ppm (1980) to ~420 ppm (2025). Concurrently, the right axis shows surface seawater pH falling from ~8.15 to ~8.05. This demonstrates an inverse correlation (\(CO_2 + H_2O \rightarrow H_2CO_3 \rightarrow H^+ + HCO_3^-\)).
Distractor Analysis: Choice A confuses acidity with alkalinity. Choice C ignores the clear empirical decline. Choice D posits cyclical variation not present in the monotonic multi-decade trend.
DAY 14 Hertzsprung-Russell Stellar Diagram
CORRECT: B
Rationale: The H-R diagram has an inverted x-axis (temperature decreases from left to right). Stars at the top-left of the Main Sequence possess both the highest luminosity (\(10^4 - 10^5 L_\odot\)) and highest temperatures (>20,000–30,000 K, blue O/B stars).
Distractor Analysis: Choice A describes red supergiants, not upper Main Sequence stars. Choice C falsely attributes long lifespan to massive luminous stars (which actually exhaust fuel quickly). Choice D ignores that white dwarfs have very low luminosity (\(10^{-2} - 10^{-4} L_\odot\)).
DAY 15 Groundwater Table vs. Precipitation
CORRECT: B
Rationale: Rainfall enters the unsaturated vadose zone and infiltrates downward at a rate dictated by soil hydraulic conductivity. This 2-month transit lag between surface precipitation (May) and phreatic aquifer recharge (July) is caused by percolation transit time.
Distractor Analysis: Choice A is disproven by the water table rising significantly later. Choice C contradicts hydrogeology. Choice D is seasonally incorrect for temperate zones.
Teacher Tip: Remind students that ACT Science questions often test physical causality behind time lags. Page 3 of 4
Teacher Reference & Answer Key
Days 16–20 Explanations
ACT Science: Conflicting Viewpoints & Synthesis
DAY 16 Hydroponic Nutrient Isolation Trials
CORRECT: A
Rationale: In a controlled experiment, only the independent variable of interest must vary. Comparing Control (10.0 mM N, 2.0 mM P) and Trial 1 (2.0 mM N, 2.0 mM P) keeps Phosphorus identical at 2.0 mM while changing only Nitrogen from 10.0 to 2.0 mM.
Distractor Analysis: Choice B varies both N and P simultaneously, confounding the causes of biomass change. Choice C also alters two variables. Choice D compares 10 vs 2 mM N, but holds P constant at 0.4 mM (also valid, but not the primary control comparison listed among choices).
DAY 17 Galactic Rotation: Observed vs. Predicted
CORRECT: A
Rationale: Standard Keplerian mechanics predicts outer stellar velocity should fall as \(v \propto 1/\sqrt{r}\). However, the observed curve stays flat at ~220 km/s out to 20 kpc. This flat rotation discrepancy is the core anomalous observation both hypotheses strive to explain.
Distractor Analysis: Choice B directly contradicts the graph. Choice C focuses on inner core radii where models largely agree. Choice D claims no discrepancy exists.
DAY 18 Standard Deviation & Error Bar Overlap
CORRECT: A
Rationale: Drug A has an error bar ranging from 60% to 70%, while Drug B ranges from 62% to 74%. Because the intervals overlap extensively (between 62% and 70%), the difference in mean performance is not statistically distinguishable without further testing.
Distractor Analysis: Drug C (87%–97%) does not overlap with Drug A or B, demonstrating a statistically distinct treatment superiority.
DAY 19 Mechanical Energy in a Simple Pendulum
CORRECT: A
Rationale: At central displacement \(x = 0\), height is at minimum (\(h = 0 \implies PE = 0\)), and velocity is at maximum (\(v = v_{max} \implies KE = E_{total}\)). Energy is conserved: \(KE + PE = E_{total}\) at all positions.
Distractor Analysis: Choice B occurs at maximum amplitude extremes (\(\pm A\)), not at equilibrium. Choice C occurs only at intermediate displacement points. Choice D violates conservation of energy.
DAY 20 Ice Sheet Mass Anomaly Extrapolation
CORRECT: C
Rationale: Over 15 years (2005–2020), mass loss reached -2,250 Gt (\(-150\) Gt/year). Over 5 additional years from 2020 to 2025, an additional loss of \(5 \times (-150) = -750\) Gt occurs. Cumulative total: \(-2,250 + (-750) = -3,000\) Gt.
Distractor Analysis: Choice A represents the 2015 loss. Choice B is the 2020 datum before the 5-year projection. Choice D assumes the loss rate doubles.
Teacher Tip: SAT Quantitative Evidence questions frequently test linear extrapolation equations: y = mx + b. Page 4 of 4
