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Forces in Action

An inquiry-based introductory physics lesson exploring Net Force, Motion, Friction, and Acceleration using the PhET Forces and Motion: Basics interactive simulation. Students investigate balanced and unbalanced forces, inertia, surface resistance, and Newton's Second Law across a structured 45–50 minute lab experience.

Ccolton.scott

Forces in Action

An inquiry-based introductory physics lesson exploring Net Force, Motion, Friction, and Acceleration using the PhET Forces and Motion: Basics interactive simulation. Students investigate balanced and unbalanced forces, inertia, surface resistance, and Newton's Second Law across a structured 45–50 minute lab experience.

Ccolton.scott

Key Socratic Question: "Once you let go of the push, what is the net force? (0 N). Why doesn't the skateboard slow down?"

Forces in Action Teacher Guide • PhET Basics Page 1 of 2

Parts 3–4 Guidance, Misconceptions, & Assessment

Teacher Resource

Part 3: Friction (Static vs. Kinetic) Opposing Force

Review Concept Briefing 3 on microscopic interlocking. Watch the opposing friction vector closely as applied force increases. Emphasize that static friction prevents motion up to the breakaway threshold (~126 N on 50 kg crate), after which sliding kinetic friction takes over.

Part 4: Acceleration (Newton's 2nd Law) \(F_{\text{net}} = m \cdot a\)

Ensure students set friction to "None" so they test pure \(F = ma\). When testing the Mystery Box with 150 N, the dial reads \(3.00\text{ m/s}^2\). Guide students to algebraically rearrange the formula: \(m = \frac{F}{a} = \frac{150}{3.00} = 50\text{ kg}\).

Top Student Misconceptions & Sim Proofs

Intuitive Misconception

Physics Reality Demonstrated in PhET

"A continuous force is required to keep an object moving." In the Motion tab, when force drops to 0, the skateboard maintains a constant speed indefinitely.

"Position on the rope gives pulling leverage in tug-of-war." In the Net Force tab, dragging a puller to the front or back knot does not alter the net force or movement.

"Heavier objects are harder to push because they have 'more gravity'." Even without friction, mass has inertia: \(a = F/m\). More mass demands more force for the same rate of acceleration.

Striving Learners (Supports)

  • Have students read Concept Briefings in pairs and highlight key terms.
  • Use the physical tug-of-war rope model before opening the sim.
  • Provide sentence frame: "When forces are balanced, the object..."

Advanced Learners (Extensions)

  • Stack two objects (crate + refrigerator = 250 kg) and find breakaway force.
  • Calculate friction coefficient: \(\mu = \frac{F_{\text{friction}}}{m \cdot 9.8}\).
  • Graph \(F\) vs \(a\) to show linear slope equals mass.

Lab Packet Evaluation Criteria (32-Point Scale)

4 - Exemplary (29–32)

All calculations accurate; synthesizes readings with sim data in explanations.

3 - Proficient (24–28)

Accurate tables; understands \(F=ma\) and inertia; minor calculation errors.

2 - Developing (18–23)

Partially completed tables; confuses constant speed with non-zero net force.

1 - Beginning (<18)

Requires significant teacher guidance to read concepts and navigate sim.

Forces in Action Teacher Guide • PhET Basics Page 2 of 2


Why (Newton's 1st Law):

Trial B: Mass vs. Inertia (50 kg Crate vs. 200 kg Refrigerator)

3 Pts

Sample Response: The 50 kg crate gained speed much more rapidly than the 200 kg refrigerator (exactly 4 times faster).
Scientific Principle: Mass is the quantitative measure of an object's inertia. The refrigerator has 4 times greater mass, meaning it possesses 4 times greater resistance to changes in its motion. Therefore, an identical 200 N force produces a much smaller rate of speed increase.

Trial C: Thought Question — Stopping Without Friction

2 Pts

Sample Response: You must apply an active force in the opposite direction (a backward push of negative force) until the speedometer drops back to 0 m/s. Without friction, the object will never stop on its own.

Forces in Motion Answer Key • PhET Basics Page 2 of 4

Part 3: Surface Friction Solutions

8 Points

Static Friction Breakaway Solutions (50 kg Crate, Medium Friction)

Push: 50 N

Friction: 50 N

Moves? NO

Push: 100 N

Friction: 100 N

Moves? NO

Push: 125 N

Friction: 125 N

Moves? NO

Breakthrough!

126 N – 128 N

Starts Sliding

1. What happened to static friction from 50 N to 100 N? Why didn't it move?

Sample Response: Static friction matched the applied force exactly (at 50 N push, friction was 50 N; at 100 N push, friction was 100 N). Because the two forces were equal and opposite, the net force was zero (\(\Sigma F = 0\text{ N}\)). An object at rest remains at rest when forces are balanced.

2. When sliding and applied force is released to 0 N, what happens?

Sample Response: Kinetic friction points in the opposite direction of motion (backward). Because there is no forward force to balance it, friction acts as an unbalanced net force that decelerates the crate until its speed reaches 0 m/s.

3. When friction is set to "Lots", what happens to the breakaway force?

Sample Response: The breakaway force increases substantially (up to ~250 N). Rougher surfaces have deeper microscopic ridges and crevices that interlock more tightly, requiring significantly greater force to shear past one another and initiate sliding.

Forces in Motion Answer Key • PhET Basics Page 3 of 4

Part 4: Newton's Second Law & Synthesis Solutions

8 Points

Object & Mass (\(m\))Applied Force (\(F_{\text{net}}\))Predicted \(a = \frac{F}{m}\)Sim Dial \(a\)Result
Crate (50 kg)100 N\(2.00\text{ m/s}^2\)\(2.00\text{ m/s}^2\)✓ Perfect Match
Bucket of Water (100 kg)150 N\(1.50\text{ m/s}^2\)\(1.50\text{ m/s}^2\)✓ Perfect Match
Girl (40 kg)200 N\(5.00\text{ m/s}^2\)\(5.00\text{ m/s}^2\)✓ Perfect Match
Mystery Gift Box [ ? ]150 NSolve for \(m\)\(3.00\text{ m/s}^2\)✓ Mass = 50 kg!

Mystery Box Solution & Algebraic Rearrangement:

\(m = \frac{F_{\text{net}}}{a} = \frac{150\text{ N}}{3.00\text{ m/s}^2} = \mathbf{50\text{ kg}}\) Award full credit for showing formula \(m = F/a\) and arriving at 50 kg.

Synthesis & Real-World Application Solutions

1. Space probe at 30,000 km/h in deep space:

Answer: Exactly 0 N (zero thrust). In the vacuum of deep space, there is zero friction or air resistance. By Newton's First Law, an object in motion continues coasting at constant velocity without any ongoing force.

2. 1,000 kg car vs 3,000 kg truck with 3,000 N force:

Answer: The 1,000 kg car accelerates 3x faster (\(a = \frac{3000}{1000} = 3\text{ m/s}^2\)) than the 3,000 kg truck (\(a = \frac{3000}{3000} = 1\text{ m/s}^2\)). Acceleration is inversely proportional to mass (\(a \propto 1/m\)).

Forces in Motion Answer Key • PhET Basics Page 4 of 4

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