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Atomic Blueprint

A targeted chemistry review and practice bundle covering atomic structure, isotopes, mass spectrometry, electron configurations, periodic families, matter classification, and physical versus chemical changes. Includes interactive review slides, a comprehensive concept review guide, an assessment-style practice worksheet, and a detailed teacher solutions guide.

Ttimothy.nixon

Atomic Blueprint

A targeted chemistry review and practice bundle covering atomic structure, isotopes, mass spectrometry, electron configurations, periodic families, matter classification, and physical versus chemical changes. Includes interactive review slides, a comprehensive concept review guide, an assessment-style practice worksheet, and a detailed teacher solutions guide.

Ttimothy.nixon

(C) Isotopes of an element have different proton counts.

(D) Neutral atoms always possess equal protons and electrons.

7. Atom X has (16p, 16n, 16e); Atom Y has (16p, 18n, 16e). They are:

(A) Isotopes of sulfur with different mass numbers.

(B) Two completely different chemical elements.

(C) Isoelectronic ions with different charges.

(D) Allotropes differing only in electron energy shells.

Set 3: Particle Diagrams & Transformations Questions 8–9

8. Dry ice (\(\text{CO}_2\)) sublimes into gas. Which statement best explains the particle-level change?

(A) Chemical change: \(\text{C}-\text{O}\) bonds break to form free carbon and oxygen atoms.

(B) Physical change: intermolecular spacing increases while \(\text{CO}_2\) molecules stay intact.

(C) Chemical change: \(\text{CO}_2\) molecules rearrange into a new compound with different properties.

(D) Physical change: \(\text{CO}_2\) splits into diatomic \(\text{C}_2\) and \(\text{O}_2\) molecules.

9. When \(\text{Pb(NO}_3)_2(aq)\) and \(2\text{KI}(aq)\) mix, a bright yellow \(\text{PbI}_2(s)\) solid precipitates:

(A) Physical change: the reactants are simply mixed and can be separated by filtration without altering bonds.

(B) Chemical change: new ionic bonds form to produce a new substance with unique chemical properties.

(C) Physical change: change of state from aqueous to solid indicates only phase transition.

(D) Chemical change: potassium atoms lose all their protons to iodine atoms.

Chemistry Interim Practice Worksheet Page 1 of 2 Periodic Table & Subatomic Dynamics

Interim Prep — Part II

Separation Schemes, Mass Spectrometry & Electron Structure

High School Chemistry

Set 4: Mixture Separation Scheme Questions 10–12

A solid mixture of Iron powder (\(\text{Fe}\)), Potassium chloride (\(\text{KCl}\)), and Silicon dioxide sand (\(\text{SiO}_2\)) is separated according to the flowchart below:

Mixture: Fe, KCl, SiO₂

→ Magnet →

Substance 1
(Extracted by magnet)

→ Add H₂O & filter →

Substance 2
(Residue on filter)

→ Evaporate filtrate →

Substance 3
(Crystals in dish)

  1. Substance 1 is isolated purely based on which property?

(A) Solubility in water

(B) Ferromagnetism

(C) Boiling point

(D) Density

  1. If \(\text{KCl}\) is soluble in water and sand is insoluble, Substance 2 is:

(A) \(\text{KCl}\) crystals

(B) Iron filings

(C) Silicon dioxide sand

(D) Water vapor

  1. The initial 3-substance blend is a _____ mixture; the filtrate before evaporation is a _____ mixture.

(A) heterogeneous; homogeneous

(B) homogeneous; heterogeneous

(C) homogeneous; homogeneous

(D) heterogeneous; heterogeneous

Set 5: Mass Spectrometry Analysis Questions 13–15

Mass Spectrum of Unknown Element Q 0 50 100% 84 86 87 88 82.6%

  1. Which numerical setup correctly calculates the average atomic mass?

(A) \((0.0056)(84) + (0.0986)(86) + (0.0700)(87) + (0.8258)(88)\)

(B) \((84 + 86 + 87 + 88) \div 4\)

(C) \([(84)(0.56)] \times [(86)(9.86)] \times [(87)(7.00)] \times [(88)(82.58)]\)

  1. With calculated mass \(\approx 87.62\text{ amu}\), Element Q is most likely:

(A) \(\text{Rb}\) (85.47)

(B) \(\text{Sr}\) (87.62)

(C) \(\text{Y}\) (88.91)

(D) \(\text{Zr}\) (91.22)

Set 6: Electron Configurations & Quantum Principles Questions 15–18

  1. Which electron configuration is impossible?

(A) \(1s^2 2s^2 2p^6 3s^1\)

(B) \(1s^2 2s^2 2p^6 2d^4 3s^2\)

(C) \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5\)

(D) \(1s^2 2s^2 2p^6 3s^2 3p^6\)

  1. Which particle is isoelectronic with \(\text{S}^{2-}\)?

(A) Oxygen atom (\(\text{O}\))

(B) Neon atom (\(\text{Ne}\))

(C) Argon atom (\(\text{Ar}\))

(D) Magnesium ion (\(\text{Mg}^{2+}\))

  1. Ground state valence configuration \(ns^2 np^3\) is in:

(A) Grp 2

(B) Grp 13

(C) Grp 15

(D) Grp 17

  1. Ground state nitrogen (\(1s^2 2s^2 2p^3\)) orbital diagram:

(A) 2s: \([\uparrow\downarrow]\)   2p: \([\uparrow\downarrow][\uparrow\ ][\ \ ]\)

(B) 2s: \([\uparrow\downarrow]\)   2p: \([\uparrow\ ][\uparrow\ ][\uparrow\ ]\)   (parallel)

(C) 2s: \([\uparrow\downarrow]\)   2p: \([\uparrow\ ][\downarrow][\uparrow\ ]\)

(D) 2s: \([\uparrow\ ]\)      2p: \([\uparrow\downarrow][\uparrow\downarrow][\ \ ]\)

Chemistry Interim Practice Worksheet Page 2 of 2 Mass Spectrometry, Flowcharts & Orbitals

Hund's Rule

Orbitals of same energy fill singly with parallel spins before pairing up.

Oxygen \(2p^4\): \([\uparrow\downarrow][\uparrow\ ][\uparrow\ ]\)

Periodic Blocks

• \(ns^2 np^1 \to\) Group 13
• \(ns^2 np^5 \to\) Halogens (Grp 17)
• Highest \(e^-\) in \(d \to\) Transition

\(\text{K}^+\) is isoelectronic with \(\text{Ar}\)

Isoelectronic species share the same total electron count Slide 4 of 6


Concept Anchor 4

Matter Classification & Separation Logic

Physical vs Chemical

Phase & Chemical Changes

  • • Sublimation (\(\text{CO}_2(s) \to \text{CO}_2(g)\)): Purely physical! Triatomic molecules stay intact.
  • • Precipitation (\(\text{Ag}^+ + \text{Cl}^- \to \text{AgCl}(s)\)): Chemical! New bonds, new substance.
  • • Pure Element: Cannot be decomposed chemically or physically.

Flowchart Separation Strategy

Step 1: Magnetism removes ferromagnetic solids.

Step 2: Water + Filtration separates soluble from insoluble.

Step 3: Boiling point differences allow distillation.

Physical separation techniques exploit differences in physical properties Slide 5 of 6


Classroom Action Plan

Mastery Checklist & Independent Practice

Ready for the Test

1

Review Guide

Keep your 2-page reference sheet out to check formulas, families, and key rules.

2

Worksheet Check

Complete the 18 authentic assessment-style problems on the practice worksheet.

3

Error Analysis

Review step-by-step solutions and eliminate common multiple-choice traps.

Goal: 100% Accuracy on Atomic & Matter Concepts Slide 6 of 6

Set 3 Solutions: Particle Transformations Test Items Q6, Q7–8, Q11 Alignment

8. Answer: (B) Physical change; \(\text{CO}_2\) molecules stay intact

Key Concept: Sublimation (\(s \to g\)) disrupts weak intermolecular forces, not covalent \(\text{C}=\text{O}\) bonds. The molecular identity remains \(\text{CO}_2\).

9. Answer: (B) Chemical change; new ionic bonds form

Key Concept: Aqueous \(\text{Pb}^{2+}\) and \(\text{I}^-\) ions form insoluble \(\text{PbI}_2(s)\) crystal lattice with distinct properties from the original soluble salts.

Chemistry Interim Solutions Guide Page 1 of 2 Subatomic Accounting & Particle Models

Teacher Key & Solutions — Part II

Mixtures, Mass Spectrometry & Quantum Architecture

Scoring & Alignment Matrix

Set 4 Solutions: Mixture Separation Flowchart Test Items Q13–16 Alignment

10. Answer: (B) Ferromagnetism

Iron powder is pulled out by the magnetic field; all other components are diamagnetic/non-magnetic.

11. Answer: (C) Sand (\(\text{SiO}_2\))

Sand is completely insoluble in water and is trapped as residue on the filter paper while \(\text{KCl}\) dissolves.

12. Answer: (A) Heterogeneous; homogeneous

Initial blend has visible distinct phases (heterogeneous); the filtered \(\text{KCl}(aq)\) is uniform down to the ion level (homogeneous).

Set 5 Solutions: Mass Spectrometry Analysis Test Items Q18, Q22, Q29–31 Alignment

13. Answer: (A) Correct Weighted Setup

\((0.0056)(84) + (0.0986)(86) + (0.0700)(87) + (0.8258)(88)\)

Abundances must be converted to fractional decimals (\(\% \div 100\)) and multiplied by respective isotopic masses before summing.

14. Answer: (B) Strontium (\(\text{Sr}\), 87.62 amu)

Reasoning: Peak 88 dominates (82.6%), pulling the weighted average close to 88 (specifically 87.62 amu), matching Strontium in Group 2.

Set 6 Solutions: Electron Configurations & Orbitals Test Items Q20, Q21, Q24–28 Alignment

15. Answer: (B) \(1s^2 2s^2 2p^6 2d^4 3s^2\) is impossible

Quantum Rule: The \(n=2\) principal energy level only has \(\ell=0\) (\(s\)) and \(\ell=1\) (\(p\)) orbitals. \(d\) subshells only begin at \(n=3\).

16. Answer: (C) Argon atom (\(\text{Ar}\))

Isoelectronic: \(\text{S}^{2-}\) has \(16 + 2 = 18\) electrons, identical to neutral \(\text{Ar}\) (\(1s^2 2s^2 2p^6 3s^2 3p^6\)).

17. Answer: (C) Group 15

Total valence electrons \(= 2 + 3 = 5\). Corresponds to the Nitrogen family (Group 15 in IUPAC numbering).

18. Answer: (B) 2s: \([\uparrow\downarrow]\) 2p: \([\uparrow\ ][\uparrow\ ][\uparrow\ ]\)

Hund's Rule: Degenerate \(2p\) orbitals must be singly occupied with parallel spins before any pairing occurs.

Quick Remediation Crosswalk (Test Item Mapping):

Missed Q1–4, 23 (Families/Safety)?
Review Guide: Domain 4. Emphasize that alkali metals react with \(H_2O\), halogens span all 3 states.

Missed Q5, 9, 10, 17 (Subatomic/Ions)?
Review Guide: Domain 1. Drill \(A = p^+ + n^0\) and \(q = p^+ - e^-\). Isotopes have equal protons!

Missed Q18, 22, 29–31 (Mass Spec)?
Review Guide: Domain 2. Review fractional abundance \(\times\) mass setup; tallest peak = most abundant isotope.

Chemistry Interim Solutions Guide Page 2 of 2 Scoring Rubric & Remediation Crosswalk

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