Stoichiometry Blueprint Worksheet
Stoichiometry Blueprint
Chemical Engineering Department • Phase II Analysis
Lead Scientist (Name)
Date
Molar Mass
Mass of 1 mole of a substance. Units: g/mol. Look this up on your Periodic Table!
Mole Ratio
Relationship between two substances. Use the coefficients from the balanced equation.
Yield Formula
Actual Yield
Theoretical Yield
× 100 = % Yield
01
The Haber Process
Synthesis of Ammonia for global fertilizer production.
N2(g) + 3 H2(g) → 2 NH3(g)
Research Scenario: A technician starts with 28.0 grams of Nitrogen (N2). Assuming excess Hydrogen, calculate the mass of Ammonia (NH3) that can be synthesized.
28.0 g N2
1
1 mole N2
_______ g N2
_______ mol NH3
_______ mol N2
_______ g NH3
1 mole NH3
=
g NH3
02
Aluminum Chloride Synthesis
Determining the limiting factor in catalyst production.
2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)
Lab Test: vessel is loaded with 54.0 g of Aluminum and 71.0 g of Chlorine gas. Which reactant is limiting?
Path A: Yield from 54.0 g Al
54.0 g Al
=
g AlCl3
Path B: Yield from 71.0 g Cl2
71.0 g Cl2
=
g AlCl3
Limiting Reactant
Theoretical Yield (g)
03
Silver Precipitation
Measuring the efficiency of silver recovery.
Cu(s) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 Ag(s)
Experiment: react 10.0 g of Copper with excess Silver Nitrate. Student recovers 25.4 g of Silver.
Step 1: Theoretical Yield of Ag (g)
10.0 g Cu
=
Step 2: Calculate Percent Yield
25.4 g (Actual)
Theoretical (from Step 1)
× 100 =
% YIELD
04
Propane Combustion
Analyzing fuel efficiency through CO2 emissions.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
Task: If 44.1 grams of Propane (C3H8) are burned, what mass of Carbon Dioxide (CO2) is released?
44.1 g C3H8
=
05
Magnesium Flare
Full analysis: Limiting Reactant and Efficiency Review.
2 Mg(s) + O2(g) → 2 MgO(s)
Lab: 48.6 g Mg reacts with 50.0 g O2. Recovered: 60.0 g MgO.
Step 1: Determine Theoretical Yield
48.6 g Mg
=
50.0 g O2
=
Limiting
Theoretical
% Yield
Stoichiometry Blueprint Answer Key
Answer Key
Stoichiometry Blueprint • Phase II Solutions
01: The Haber Process
Calculation:
28.0 g N2
1
1 mol N2
28.02 g N2
2 mol NH3
1 mol N2
17.03 g NH3
1 mol NH3
= 34.0 g NH3
Result: Theoretical Yield is 34.0 grams of NH3.
02: Aluminum Chloride Synthesis
Calculation A (Aluminum):
54.0 g Al
1
1 mol Al
26.98 g
2 mol AlCl3
2 mol Al
133.33 g
1 mol
= 266.9 g AlCl3
Calculation B (Chlorine):
71.0 g Cl2
1
1 mol Cl2
70.90 g
2 mol AlCl3
3 mol Cl2
133.33 g
1 mol
= 88.9 g AlCl3
Limiting Reactant
Chlorine (Cl2)
Theoretical Yield
88.9 g AlCl3
03: Silver Precipitation
Theoretical Yield Calculation:
10.0 g Cu
1
1 mol Cu
63.55 g
2 mol Ag
1 mol Cu
107.87 g
1 mol Ag
= 33.9 g Ag
Percent Yield:
25.4 g (Actual)
33.9 g (Theo.)
× 100 =
74.9%
04: Propane Combustion
Calculation:
44.1 g C3H8
1
1 mol C3H8
44.11 g
3 mol CO2
1 mol
44.01 g CO2
1 mol
= 132.0 g CO2
Result: 132.0 grams of CO2 released.
05: Magnesium Flare
Yield from 48.6 g Mg:
48.6 g Mg
1
1 mol Mg
24.31 g
2 mol MgO
2 mol Mg
40.31 g
1 mol
= 80.6 g MgO
Yield from 50.0 g O2:
50.0 g O2
1
1 mol O2
32.00 g
2 mol MgO
1 mol O2
40.31 g
1 mol
= 126.0 g MgO
