| 2.0 | 12.0 |
| 4.0 | 6.0 |
| 8.0 | 3.0 |
MODEL #4 CUT-A4
\( y = kx^2 \)
Independent Variable (x) Dep. (y)
SCENARIO CUT-B4
Calculating kinetic energy \( (K) \) of a sliding hockey puck with a mass of \( 2.0\text{ kg} \) as it flies at different velocities \( (v) \).
Model: \( K = v^2 \)
DATA TABLE CUT-C4
| Speed \( v \) (m/s) | Energy \( K \) (J) |
|---|---|
| 1.0 | 1.0 |
| 3.0 | 9.0 |
| 5.0 | 25.0 |
MODEL #5 CUT-A5
\( y = k\sqrt{x} \)
Independent Variable (x) Dep. (y)
SCENARIO CUT-B5
Measuring oscillation period \( (T) \) of a heavy brass pendulum as its suspension wire length \( (L) \) is extended.
Model: \( T = 2.0\sqrt{L} \)
DATA TABLE CUT-C5
| Length \( L \) (m) | Period \( T \) (s) |
|---|---|
| 1.0 | 2.0 |
| 4.0 | 4.0 |
| 9.0 | 6.0 |
Interactive Card Activity • Cut-and-Align Guide • Physics Graphing Sequence
| 3.0 | 15.0 |
Page 1 • Types of Graph - Summary
PHYSICS CORE SYSTEM
Analyzing Curves in Action: This section transitions into nonlinear behaviors. Some physics variables drop rapidly as they scale, while others rise exponentially. Study the concise scientific readings, theoretical models, and pre-drawn plots.
03
An inverse relationship occurs when one variable increases while the other decreases proportionally. Newton's Second Law demonstrates this: if you push carts of different masses with a constant force, the acceleration decreases as mass increases (\( a = F/m \)). Tripling the mass reduces acceleration to one-third of its original value. When plotted, this data forms a curving hyperbola that approaches the axes but never touches them.
Model: \( y = \frac{k}{x} \) | Shape: ____________________________
If mass triples, acceleration drops to ___________ of its original value.
Partner Share: Summarize 2 key points to share with your partner:
a (m/s²)
m (kg)
| Mass (kg) | Acc. (m/s²) |
|---|---|
| 2.0 | 12.0 |
| 4.0 | 6.0 |
| 8.0 | 3.0 |
04
A square relationship represents a power law where the dependent variable is proportional to the square of the independent variable. In kinetic energy experiments, a vehicle's energy scales with the square of its speed (\( KE = \frac{1}{2}mv^2 \)). Doubling the speed of the vehicle quadruples its kinetic energy, while tripling speed increases energy ninefold. This yields an upward-curving parabola starting at the origin.
Model: \( y = kx^2 \) | Shape: _______________________________
If velocity triples, kinetic energy will scale by a factor of __________ .
Partner Share: Summarize 2 key points to share with your partner:
K (J)
v (m/s)
| Speed (v) | Energy (K) |
|---|---|
| 1.0 | 1.0 |
| 3.0 | 9.0 |
| 5.0 | 25.0 |
Page 2 • Types of Graph - Summary
PHYSICS CORE SYSTEM
05
A square root relationship is the inverse of a square relationship, where the dependent variable is proportional to the square root of the independent variable. For instance, the period of a simple pendulum is proportional to the square root of its suspension length (\( T \propto \sqrt{L} \)). To double the time it takes for a pendulum to swing, the string length must be quadruled. This curves upward from the origin and slowly flattens out as length stretches.
Model: \( y = k\sqrt{x} \) | Shape: __________________________
To double the swing period, the length must increase by a factor of ____________ .
Partner Share: Summarize 2 key points to share with your partner:
T (s)
L (m)
| Length (m) | Period (s) |
|---|---|
| 1.0 | 2.0 |
| 4.0 | 4.0 |
| 9.0 | 6.0 |
STUDENT REFERENCE MATRIX
| Relationship Name | Mathematical Equation (Fill-in) | Graphical Curve Profile (Fill-in) |
|---|---|---|
| Constant | ||
| | Linear |
|
| | Inverse |
|
| | Square |
|
| | Square Root |
|
|
Quick Comprehension Check
A lab team plotting acceleration vs. mass got a curving hyperbola. They want to find the applied force, which is the constant \( F \) in \( a = F(1/m) \).
Q1: What should they plot on the X-axis to linearize? ______________________________________________
Q2: What will the slope of the linearized graph equal? ______________________________________________
Page 3 • Types of Graph - Summary
1. Direct proportionality means doubling one variable exactly doubles the other.
2. The slope represents a physical constant of the system, such as electrical resistance \( R \).
V (V)
I (A)
| Current (A) | Voltage (V) |
|---|---|
| 1.0 | 5.0 |
| 2.0 | 10.0 |
| 3.0 | 15.0 |
Teacher Key • Page 1 • Types of Graph Summary
Teacher Answer Key
PHYSICS KEY PACKET
Analyzing Curves in Action: This section transitions into nonlinear behaviors. Some physics variables drop rapidly as they scale, while others rise exponentially. Study the concise scientific readings, theoretical models, and pre-drawn plots.
03
An inverse relationship occurs when one variable increases while the other decreases proportionally. Newton's Second Law demonstrates this: if you push carts of different masses using a constant force, the acceleration decreases as mass increases (\( a = F/m \)). Tripling the mass reduces acceleration to one-third of its original value. When plotted, this data forms a curving hyperbola that approaches the axes but never touches them.
Model: \( y = \frac{k}{x} \)
Shape: Hyperbola (Downward Curve)
If mass triples, acceleration drops to one-third (1/3) of its original value.
Partner Share: Summarize 2 key points to share with your partner:
1. As the independent variable increases, the dependent variable decreases at a scaling rate.
2. The curve is an asymptotic hyperbola which never crosses either axis.
a (m/s²)
m (kg)
| Mass (kg) | Acc. (m/s²) |
|---|---|
| 2.0 | 12.0 |
| 4.0 | 6.0 |
| 8.0 | 3.0 |
04
A square relationship represents a power law where the dependent variable is proportional to the square of the independent variable. In kinetic energy experiments, a vehicle's energy scales with the square of its speed (\( KE = \frac{1}{2}mv^2 \)). Doubling the speed of the vehicle quadruples its kinetic energy, while tripling speed increases energy ninefold. This yields an upward-curving parabola starting at the origin.
Model: \( y = kx^2 \)
Shape: Upward-Curving Parabola
If velocity triples, kinetic energy will scale by a factor of 9 (nine) .
Partner Share: Summarize 2 key points to share with your partner:
1. The dependent variable changes in proportion to the square of the independent variable.
2. Tripling the independent variable results in a 9x increase in the dependent variable.
K (J)
v (m/s)
| Speed (v) | Energy (K) |
|---|---|
| 1.0 | 1.0 |
| 3.0 | 9.0 |
| 5.0 | 25.0 |
Teacher Key • Page 2 • Types of Graph Summary
Teacher Answer Key
PHYSICS KEY PACKET
05
A square root relationship is the inverse of a square relationship, where the dependent variable is proportional to the square root of the independent variable. For instance, the period of a simple pendulum is proportional to the square root of its suspension length (\( T \propto \sqrt{L} \)). To double the time it takes for a pendulum to swing, the string length must be quadruled. This curves upward from the origin and slowly flattens out as length stretches.
Model: \( y = k\sqrt{x} \)
Shape: Upward Curve (Gradually Flattening)
To double the swing period, the length must increase by a factor of 4 (four) .
Partner Share: Summarize 2 key points to share with your partner:
1. The dependent variable increases rapidly initially, then slows down as X increases.
2. Doubling the output (period) requires quadrupling (4x) the input parameter (length).
T (s)
L (m)
| Length (m) | Period (s) |
|---|---|
| 1.0 | 2.0 |
| 4.0 | 4.0 |
| 9.0 | 6.0 |
COMPLETED REFERENCE MATRIX
Answers
| Relationship Name | Mathematical Equation | Graphical Curve Profile |
|---|---|---|
| Constant | \( y = C \) (Slope = 0) | Flat horizontal line |
| Linear | \( y = mx \) (or \( y = mx + b \)) | Straight diagonal line through origin |
| Inverse | \( y = \frac{k}{x} \) (or \( y = kx^{-1} \)) | Downward-sloping hyperbola |
| Square | \( y = kx^2 \) | Upward-curving parabola through origin |
| Square Root | \( y = k\sqrt{x} \) (or \( y = kx^{1/2} \)) | Upward curve that gradually flattens |
Quick Comprehension Check (Solved)
A lab team plotting acceleration vs. mass got a curving hyperbola. They want to find the applied force, which is the constant \( F \) in \( a = F(1/m) \).
Q1: What should they plot on the X-axis to linearize? Plot \( 1/m \) (inverse mass) on the X-axis.
Q2: What will the slope of the linearized graph equal? The slope of the line will equal the applied force, \( F \).
Teacher Key • Page 3 • Types of Graph Summary