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Slope Review

A comprehensive pre-algebra lesson reviewing how to determine the slope of a line from graphs, pairs of coordinate points, and linear equations.

FMFernando Mancini

Slope Review

A comprehensive pre-algebra lesson reviewing how to determine the slope of a line from graphs, pairs of coordinate points, and linear equations.

FMFernando Mancini

\(m =\) \(-\frac{4}{15}\)

\(m = \frac{14 - 10}{-7 - 8} = \frac{4}{-15}\)

\(= -\frac{4}{15}\)

  1. \((-3, 1)\) and \((-17, 2)\)

\(m =\) \(-\frac{1}{14}\)

\(m = \frac{2 - 1}{-17 - (-3)} = \frac{1}{-14}\)

\(= -\frac{1}{14}\)

  1. \((-20, -4)\) and \((-12, -10)\)

\(m =\) \(-\frac{3}{4}\)

\(m = \frac{-10 - (-4)}{-12 - (-20)} = \frac{-6}{8}\)

\(= -\frac{3}{4}\)

  1. \((-12, -5)\) and \((0, -8)\)

\(m =\) \(-\frac{1}{4}\)

\(m = \frac{-8 - (-5)}{0 - (-12)} = \frac{-3}{12}\)

\(= -\frac{1}{4}\)

  1. \((-19, -6)\) and \((15, 16)\)

\(m =\) \(\frac{11}{17}\)

\(m = \frac{16 - (-6)}{15 - (-19)} = \frac{22}{34}\)

\(= \frac{11}{17}\)

  1. \((-6, 9)\) and \((7, -9)\)

\(m =\) \(-\frac{18}{13}\)

\(m = \frac{-9 - 9}{7 - (-6)} = \frac{-18}{13}\)

\(= -\frac{18}{13}\)

  1. \((-18, -20)\) and \((-18, -15)\)

\(m =\) Undefined

\(m = \frac{-15 - (-20)}{-18 - (-18)} = \frac{5}{0}\)

Division by 0 → Undefined

  1. \((12, -18)\) and \((11, 12)\)

\(m =\) \(-30\)

\(m = \frac{12 - (-18)}{11 - 12} = \frac{30}{-1}\)

\(= -30\)

Part 3: Find the Slope of Each Line Compare to \(y = mx + b\)

  1. \(y = -5x - 1\)

\(m =\) \(-5\)

  1. \(y = \frac{1}{3}x - 4\)

\(m =\) \(\frac{1}{3}\)

  1. \(y = -\frac{1}{5}x - 4\)

\(m =\) \(-\frac{1}{5}\)

  1. \(x = 1\) (vertical)

\(m =\) Undefined

  1. \(y = \frac{1}{4}x + 1\)

\(m =\) \(\frac{1}{4}\)

  1. \(y = -\frac{2}{3}x - 1\)

\(m =\) \(-\frac{2}{3}\)

  1. \(y = -x + 2\)

\(m =\) \(-1\)

  1. \(y = -x - 1\)

\(m =\) \(-1\)

  1. \(2x + 3y = 9\) Worked Solution

\(3y = -2x + 9\)

\(y = -\frac{2}{3}x + 3\)

Final Slope:

\(m =\) \(-\frac{2}{3}\)

  1. \(5x + 2y = 6\) Worked Solution

\(2y = -5x + 6\)

\(y = -\frac{5}{2}x + 3\)

Final Slope:

\(m =\) \(-\frac{5}{2}\)

Pre-Algebra Slope Review Answer Key • All 26 Problems Fully Solved. Page 2 of 2

Independent Practice

Slope Formula Practice Problems

Name:

Date:

Per:

Find the slope of the line passing through each pair of points. Show your work. \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

  1. \((4, 7)\) and \((8, 19)\)

\(m =\)

  1. \((-1, 9)\) and \((3, 1)\)

\(m =\)

  1. \((-6, -2)\) and \((2, 2)\)

\(m =\)

  1. \((5, -8)\) and \((-3, 4)\)

\(m =\)

  1. \((-7, 3)\) and \((-7, 11)\)

\(m =\)

  1. \((10, -4)\) and \((-2, -4)\)

\(m =\)

  1. \((-4, -9)\) and \((6, 6)\)

\(m =\)

  1. \((3, -15)\) and \((-5, 17)\)

\(m =\)

Error Detective: Find & Explain the Mistake!

A student was asked to find the slope between \((2, 5)\) and \((7, 1)\). Here is their work:

\(m = \frac{7 - 2}{1 - 5} = \frac{5}{-4} = -\frac{5}{4}\)

What error did the student make, and what is the correct slope?

Completed all 12 practice problems! Ensure all fractional slopes are reduced to simplest form. Page 2 of 2

Guided Practice Solutions Complete • Check student work for subtracting negative numbers. Page 1 of 2

Independent Practice

Slope Formula Practice Solutions • Problems 5–12

Page 2 Solutions

Independent Practice: Full Substitution & Reduction Steps \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

  1. \((4, 7)\) and \((8, 19)\)

\(m =\) \(3\)

\(m = \frac{19 - 7}{8 - 4} = \frac{12}{4}\)

\(= 3\)

  1. \((-1, 9)\) and \((3, 1)\)

\(m =\) \(-2\)

\(m = \frac{1 - 9}{3 - (-1)} = \frac{-8}{3 + 1} = \frac{-8}{4}\)

\(= -2\)

  1. \((-6, -2)\) and \((2, 2)\)

\(m =\) \(\frac{1}{2}\)

\(m = \frac{2 - (-2)}{2 - (-6)} = \frac{2 + 2}{2 + 6} = \frac{4}{8}\)

\(= \frac{1}{2}\)

  1. \((5, -8)\) and \((-3, 4)\)

\(m =\) \(-\frac{3}{2}\)

\(m = \frac{4 - (-8)}{-3 - 5} = \frac{4 + 8}{-8} = \frac{12}{-8}\)

\(= -\frac{3}{2}\)

  1. \((-7, 3)\) and \((-7, 11)\)

\(m =\) Undefined

\(m = \frac{11 - 3}{-7 - (-7)} = \frac{8}{-7 + 7} = \frac{8}{0}\)

Division by zero → Undefined (Vertical)

  1. \((10, -4)\) and \((-2, -4)\)

\(m =\) \(0\)

\(m = \frac{-4 - (-4)}{-2 - 10} = \frac{-4 + 4}{-12} = \frac{0}{-12}\)

\(= 0\) (Horizontal Line)

  1. \((-4, -9)\) and \((6, 6)\)

\(m =\) \(\frac{3}{2}\)

\(m = \frac{6 - (-9)}{6 - (-4)} = \frac{6 + 9}{6 + 4} = \frac{15}{10}\)

\(= \frac{3}{2}\)

  1. \((3, -15)\) and \((-5, 17)\)

\(m =\) \(-4\)

\(m = \frac{17 - (-15)}{-5 - 3} = \frac{17 + 15}{-8} = \frac{32}{-8}\)

\(= -4\)

Error Detective • Model Explanation & Solution

Correct Slope: \(m = -\frac{4}{5}\)

The Mistake: The student put the \(x\)-values in the numerator and the \(y\)-values in the denominator (\(\frac{\Delta x}{\Delta y}\) instead of \(\frac{\Delta y}{\Delta x}\)). Slope is always \(\frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}\)!

Correct Calculation: \(m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{7 - 2} = \frac{-4}{5} = \mathbf{-\frac{4}{5}}\).

Two Point Slope Worksheet Answer Key Complete • All 12 problems & error analysis solved. Page 2 of 2

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