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Inequality Showdown

An Algebra 1 lesson on solving multistep linear inequalities featuring distribution, moving terms across the line, and flipping the inequality symbol when dividing by negative coefficients.

HHarlston

Inequality Showdown

An Algebra 1 lesson on solving multistep linear inequalities featuring distribution, moving terms across the line, and flipping the inequality symbol when dividing by negative coefficients.

HHarlston

August 2022 #21 (Adapted)

Correct Option: Choice (2): \(x < -2\)

Graph Feature: Open Circle at \(-2\), Ray Left

Key Move: Flip \(>\) to \(<\) (Divide by -3.5)

2. What is the solution to the linear inequality for \(x\)?

\(-0.5(4x - 6)\) > \(1.5x + 10\)

Model Step: Distribute \(-0.5\): \((-0.5 \cdot 4x) + (-0.5 \cdot -6) = -2x + 3\). Right side is already expanded: \(1.5x + 10\).

Step 1 Master Key: Decimal terms correctly distributed, aligned, and grouped across the line

Circle Team (Move Right • Change Sign!)

X-Box Team (Move Left • Change Sign!)

X-Box

-2x

Circle

+3

>

X-Box

+1.5x

Circle

+10

+ Moved X-Box (Cross Left)

-1.5x

>

+ Moved Circle (Cross Right)

-3

Combined X-Box: \(-2x - 1.5x\)

-3.5x

>

Combined Circle: \(10 - 3\)

7

> "Cross the Line... Change the Sign!" (± flippers verified) >

Division by Negative Decimal Rule Applied: Critical Step

Divide both sides by -3.5: \(\frac{-3.5x}{-3.5} \implies x\), \(\frac{7}{-3.5} \implies -2\). Because we divided by a negative number, flip > to <. Teacher Tip: Students who get \(x > -2\) missed the flip; students who get \(x < -5\) made an addition error with circles.

Final Solution: \(x\)

<

Flipped Symbol

-2

Final Value

Regents Multiple Choice Key & Distractor Rationale: Option (2) is Correct

(1) \(x > -2\)

Forgot symbol flip

(2) \(x < -2\)

CORRECT ANSWER

(3) \(x > 2\)

Sign & flip error

(4) \(x < -5\)

Constant move error

Number Line Plot Key:

Open Circle at -2 Solid Dot at ---

Ray: Left (<) Right

-6 -5 -4 -3 -2 -1 0

TI-Nspire Check Solution Key 1. Test point in ray: store -3 → x • 2. Evaluate: \(-0.5(4(-3)-6) > 1.5(-3)+10 \implies 9 > 5.5\) → Output: "true".

VERIFIED TRUE

Equipo Círculo (¡A la derecha • Cambia el signo!)

Equipo Casillero X (¡A la izquierda • Cambia el signo!)

Casillero X

Círculo

>

Casillero X

Círculo

+ Casillero X movido

>

+ Círculo movido

Casillero X combinado:

>

Círculo combinado:

> "¡Cruza la línea... cambia el signo!" >

!

¡Paso Final: Divide entre el coeficiente negativo! ¡Divide ambos lados entre el coeficiente! Como divides entre un NÚMERO NEGATIVO: ¡DEBES INVERTIR EL SÍMBOLO DE LA DESIGUALDAD!

Solución Final: \(x\)

Símbolo

Valor

Selecciona la opción Regents correspondiente: Encierra en un círculo una opción

(1) \(x > -2\)

(2) \(x < -2\)

(3) \(x > 2\)

(4) \(x < -5\)

Gráfica en la Recta Numérica:

Círculo abierto en   Punto cerrado en  

Semirrecta: Izquierda Derecha

-6 -5 -4 -3 -2 -1 0

Comprobación TI-Nspire • ¡Prueba un valor en tu semirrecta! 1. Guarda una solución de prueba de tu semirrecta:   → x • 2. Escribe: -0.5(4x - 6) > 1.5x + 10 → ENTER → verifica "true"!

Verificado "TRUE"

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