SPED Checkpoint

Have students use the color-coded visual template provided on their worksheet page to align numbers correctly.

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 1 OF 6 ENG-TEACHER-REV.01

Guided Teacher Solution Key

WEEK 2: SYSTEMS OF EQUATIONS KEYS

6-Week Pacing

Teacher Name:

Class Period:

School Year:

Question 6

Substitution

\( y = 2x - 3 \)
\( x + y = 9 \)

Ans: \( (4, 5) \)

Step-by-Step Solution

1. Substitute: \( x + (2x - 3) = 9 \)
2. Combine: \( 3x - 3 = 9 \Rightarrow 3x = 12 \Rightarrow x = 4 \)
3. Find y: \( y = 2(4) - 3 = 5 \)
4. Coordinate: \( \mathbf{(4, 5)} \)

SPED Checkpoint

Remind students they are not done when they find \( x = 4 \). They must plug it back in to get their \( y \) coordinate!

Question 7

Elimination

\( 2x + 3y = 11 \)
\( 2x - y = 3 \)

Ans: \( (2.5, 2) \)

Step-by-Step Solution

1. Subtract: \( (2x-2x) + (3y-(-y)) = 11-3 \)
2. Simplify: \( 4y = 8 \Rightarrow y = 2 \)
3. Find x: \( 2x - (2) = 3 \Rightarrow 2x = 5 \Rightarrow x = 2.5 \)
4. Coordinate: \( \mathbf{(2.5, 2)} \)

SPED Checkpoint

Double negative error: students subtract \( 3y - y \) instead of \( 3y - (-y) \). Remind them: subtraction flips the sign!

Question 8

Solve by Graphing

\( y = x + 2 \)
\( y = -x + 4 \)

Ans: \( (1, 3) \)

Step-by-Step Solution

1. Graph line 1: y-int = 2, slope = 1.
2. Graph line 2: y-int = 4, slope = -1.
3. Find their intersection. It is point \( \mathbf{(1, 3)} \).
4. Verify coordinates using expanded axis numbers (-5 to 5).

SPED Checkpoint

Students struggle to locate points on empty grids. Have them point out the printed vertical axis label \( 3 \) and horizontal \( 1 \) explicitly on the expanded graph.

Question 9

System Word Prob

Sum = 15, Diff = 3

Ans: \( 9 \) and \( 6 \)

Step-by-Step Solution

1. System: \( x+y=15 \), \( x-y=3 \)
2. Add equations: \( 2x = 18 \Rightarrow x = 9 \)
3. Substitute: \( 9 + y = 15 \Rightarrow y = 6 \)
4. Solution: The numbers are \( \mathbf{9} \) and \( \mathbf{6} \).

SPED Checkpoint

For SPED support, the pre-written system formulas on their sheets prevent writing frustration and speed up lesson pacing.

Question 10

Special Systems

\( 2x - y = 4 \)
\( -4x + 2y = -8 \)

Ans: Infinite Sol.

Step-by-Step Solution

1. Multiply Eq 1 by -2: \( -4x + 2y = -8 \)
2. Notice it is identical to Eq 2.
3. Subtracting gives \( 0 = 0 \) (True).
4. Conclusion: Infinite Solutions.

SPED Checkpoint

If equations are completely identical (same slope and same intercept), it's the exact same line, meaning Infinite Solutions.

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 2 OF 6 ENG-TEACHER-REV.01

Guided Teacher Solution Key

WEEK 3: QUADRATIC FUNCTIONS KEYS

6-Week Pacing

Teacher Name:

Class Period:

School Year:

Question 11

Trinomial Factoring

\( x^2 - 5x - 6 \)

Ans: \( (x-6)(x+1) \)

Step-by-Step Solution

1. Multiply to \( c = -6 \).
2. Add to \( b = -5 \).
3. Test factors: \( -6 \times 1 = -6 \) and \( -6 + 1 = -5 \).
4. Solution: \( \mathbf{(x - 6)(x + 1)} \)

SPED Checkpoint

Show students why \( (x-2)(x-3) \) fails: their product is \( +6 \) instead of \( -6 \). Emphasize sign verification.

Question 12

Quadratic Formula

\( x^2 - 4x + 3 = 0 \)

Ans: \( x = 3, 1 \)

Step-by-Step Solution

1. Plug in values: \( a=1, b=-4, c=3 \).
2. Discriminant: \( \sqrt{(-4)^2 - 4(1)(3)} = \sqrt{16-12} = 2 \).
3. Split: \( x = \frac{4 \pm 2}{2} \).
4. Answer: \( \mathbf{x = 3} \) or \( \mathbf{x = 1} \).

SPED Checkpoint

For SPED accommodation, the printed formula template in their packet reduces cognitive load and visual search blocks.

Question 13

Parabola Features

\( y = x^2 - 2x - 3 \)

Ans: Vertex \( (1, -4) \)

Step-by-Step Solution

1. Axis of symmetry: \( x = -\frac{b}{2a} = -\frac{-2}{2(1)} = 1 \).
2. Vertex y: \( y = (1)^2 - 2(1) - 3 = -4 \).
3. Vertex coordinates: \( \mathbf{(1, -4)} \).
4. y-intercept is \( (0, -3) \).

SPED Checkpoint

Check their calculation of axis of symmetry: \( -b/2a \). Double negatives often turn positive here: \( -(-2) = +2 \).

Question 14

Solve by Factoring

\( 2x^2 + 5x - 3 = 0 \)

Ans: \( x = \frac{1}{2}, -3 \)

Step-by-Step Solution

1. Factor: \( (2x - 1)(x + 3) = 0 \).
2. Set 1: \( 2x - 1 = 0 \Rightarrow x = 0.5 \).
3. Set 2: \( x + 3 = 0 \Rightarrow x = -3 \).
4. Roots: \( \mathbf{x = 0.5} \) and \( \mathbf{x = -3} \).

SPED Checkpoint

For SPED support, we provide the factored template clue so they can practice the critical zero-product property without getting stuck factoring.

Question 15

Vertex Form

\( y = 2(x + 3)^2 - 4 \)

Ans: Vertex \( (-3, -4) \)

Step-by-Step Solution

1. Compare to \( y = a(x-h)^2 + k \).
2. Find \( h \): \( x+3 \rightarrow h = -3 \) (sign flips!).
3. Find \( k \): \( k = -4 \).
4. Axis of symmetry: \( \mathbf{x = -3} \), Opens: UP.

SPED Checkpoint

Remind students: "Inside parentheses, the sign is the opposite of what you see. Outside parentheses, the sign stays same."

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 3 OF 6 ENG-TEACHER-REV.01

Guided Teacher Solution Key

WEEK 4: EXPONENTS & RADICALS KEYS

6-Week Pacing

Teacher Name:

Class Period:

School Year:

Question 16

Exponents Rules

\( (2x^3 y^{-2})^4 \)

Ans: \( \frac{16x^{12}}{y^8} \)

Step-by-Step Solution

1. Apply power: \( 2^4 \cdot (x^3)^4 \cdot (y^{-2})^4 \).
2. Coefficient: \( 2^4 = 16 \).
3. Powers: \( 16 \cdot x^{12} \cdot y^{-8} \).
4. Move negative: \( \mathbf{\frac{16x^{12}}{y^8}} \).

SPED Checkpoint

Check that students apply the power of 4 to the number coefficient \( 2 \), not just the variables. Students often write \( 2x^{12} \).

Question 17

Simplifying Radicals

\( \sqrt{72} \) and \( \sqrt{48x^5} \)

Ans: \( 6\sqrt{2} \), \( 4x^2\sqrt{3x} \)

Step-by-Step Solution

Part A: \( \sqrt{36 \cdot 2} = \mathbf{6\sqrt{2}} \).
Part B: \( \sqrt{16x^4 \cdot 3x} = \sqrt{16} \cdot \sqrt{x^4} \cdot \sqrt{3x} \)
            \( = \mathbf{4x^2\sqrt{3x}} \).

SPED Checkpoint

Use the printed perfect squares reference on their sheets to identify factors: \( 36 \) for \( 72 \) and \( 16 \) for \( 48 \).

Question 18

Radical Operations

\( \sqrt{3} \cdot \sqrt{12} \) & \( \frac{\sqrt{50}}{\sqrt{2}} \)

Ans: \( 6 \) and \( 5 \)

Step-by-Step Solution

Part A: \( \sqrt{3 \cdot 12} = \sqrt{36} = \mathbf{6} \).
Part B: \( \sqrt{\frac{50}{2}} = \sqrt{25} = \mathbf{5} \).

SPED Checkpoint

Ensure students fully simplify. They often write \( \sqrt{36} \) and stop, forgetting that \( 36 \) has a clean square root of \( 6 \).

Question 19

Scientific Notation

\( (3 \times 10^4) \times (4 \times 10^5) \)

Ans: \( 1.2 \times 10^{10} \)

Step-by-Step Solution

1. Multiply values: \( 3 \times 4 = 12 \).
2. Add powers: \( 10^{4+5} = 10^9 \).
3. Combine: \( 12 \times 10^9 \).
4. Shift decimal: \( \mathbf{1.2 \times 10^{10}} \).

SPED Checkpoint

Check the final conversion step. Students will often leave the result as \( 12 \times 10^9 \), violating standard scientific notation rules.

Question 20

Fractional Exp

\( 27^{2/3} \) and \( 16^{-1/2} \)

Ans: \( 9 \), \( \frac{1}{4} \)

Step-by-Step Solution

Part A: \( (\sqrt[3]{27})^2 = 3^2 = \mathbf{9} \).
Part B: \( \frac{1}{16^{1/2}} = \frac{1}{\sqrt{16}} = \mathbf{\frac{1}{4}} \).

SPED Checkpoint

Model the fraction conversion rules clearly. Check that they do not multiply the base by the fraction exponent (e.g. \( 27 \times 2/3 = 18 \)).

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 4 OF 6 ENG-TEACHER-REV.01

Guided Teacher Solution Key

WEEK 5: POLYNOMIALS & FACTORING KEYS

6-Week Pacing

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Class Period:

School Year:

Question 21

Factor out a GCF

\( 6x^3 - 15x^2 + 9x \)

Ans: \( 3x(2x^2 - 5x + 3) \)

Step-by-Step Solution

1. Coefficients: \( 6, -15, 9 \rightarrow \) GCF is \( 3 \).
2. Variable parts: \( x^3, x^2, x \rightarrow \) GCF is \( x \).
3. Combine: GCF is \( \mathbf{3x} \).
4. Divide terms: \( \mathbf{3x(2x^2 - 5x + 3)} \).

SPED Checkpoint

Students commonly factor out only the number \( 3 \) and forget to pull out the variable \( x \), leaving higher powers inside.

Question 22

Multiply Binomials

\( (2x + 3)(x - 5) \)

Ans: \( 2x^2 - 7x - 15 \)

Step-by-Step Solution

1. First: \( 2x \cdot x = 2x^2 \).
2. Outer/Inner: \( -10x + 3x = -7x \).
3. Last: \( 3 \cdot (-5) = -15 \).
4. Combine: \( \mathbf{2x^2 - 7x - 15} \).

SPED Checkpoint

Check the Last term: students may add \( 3 + (-5) = -2 \) instead of multiplying to get \( -15 \). Emphasize multiplication.

Question 23

Difference of Squares

\( 4x^2 - 25 \)

Ans: \( (2x-5)(2x+5) \)

Step-by-Step Solution

1. Form: \( a^2 - b^2 \).
2. Find \( a \): \( \sqrt{4x^2} = 2x \).
3. Find \( b \): \( \sqrt{25} = 5 \).
4. Plug in: \( \mathbf{(2x - 5)(2x + 5)} \).

SPED Checkpoint

Students often forget to write the two opposite signs, incorrectly factoring to \( (2x - 5)^2 \) which has a middle term.

Question 24

Subtract Polynomials

\( (3x^2 + 5x - 6) \)
\( - (x^2 - 2x + 4) \)

Ans: \( 2x^2 + 7x - 10 \)

Step-by-Step Solution

1. Distribute: \( -x^2 + 2x - 4 \).
2. Combine \( x^2 \): \( 3x^2 - x^2 = 2x^2 \).
3. Combine \( x \): \( 5x + 2x = 7x \).
4. Combine constants: \( -6 - 4 = -10 \).
5. Result: \( \mathbf{2x^2 + 7x - 10} \).

SPED Checkpoint

The warning clue box on the student sheet is crucial. Ensure they distribute the negative to ALL three terms inside the second set.

Question 25

Perfect Squares

\( x^2 + 10x + 25 \)

Ans: \( (x + 5)^2 \)

Step-by-Step Solution

1. Multiply to \( c = 25 \), Add to \( b = 10 \).
2. Factors: \( 5 \) and \( 5 \).
3. Write factors: \( (x + 5)(x + 5) \).
4. Simplify: \( \mathbf{(x + 5)^2} \).

SPED Checkpoint

Some students write \( (x + 25)(x + 1) \) because they see \( 25 \). Direct them to verify if those terms add up to \( 10 \).

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 5 OF 6 ENG-TEACHER-REV.01

Guided Teacher Solution Key

WEEK 6: FUNCTIONS & GRAPHS KEYS

6-Week Pacing

Teacher Name:

Class Period:

School Year:

Question 26

Function Notation

\( f(x) = -3x + 8 \)

Ans: \( f(4) = -4 \)

Step-by-Step Solution

1. Plug in \( x = 4 \).
2. Compute: \( -3(4) + 8 \).
3. Multiply: \( -12 + 8 \).
4. Solve: \( \mathbf{f(4) = -4} \).

SPED Checkpoint

Check for integer addition errors: \( -12 + 8 \). Students might mistakenly calculate positive \( 4 \) or \( -20 \).

Question 27

Domain and Range

\( \{ (2,3), (4,-1), (6,5), (8,3) \} \)

D:\(\{2,4,6,8\}\) | R:\(\{-1,3,5\}\)

Step-by-Step Solution

1. Domain = list of inputs: \( \mathbf{\{2, 4, 6, 8\}} \).
2. Range = list of outputs: \( \mathbf{\{-1, 3, 5\}} \).
3. Note: Repeats in range (the \( 3 \)) are only listed once.

SPED Checkpoint

Make sure students write the range values from least to greatest and do not write duplicate \( 3 \)'s.

Question 28

Slope from Table

y increases by 6
x increases by 2

Ans: \( m = 3 \)

Step-by-Step Solution

1. Change in \( y = 11 - 5 = 6 \).
2. Change in \( x = 3 - 1 = 2 \).
3. Slope \( m = \frac{\Delta y}{\Delta x} = \frac{6}{2} \).
4. Solve: \( \mathbf{m = 3} \).

SPED Checkpoint

A common mistake is putting change of x over change of y, resulting in a slope of \( 1/3 \). Emphasize "rise over run".

Question 29

Linear vs. Exponential

A: Doubles
B: constant rate

A: Exp  |  B: Linear

Step-by-Step Solution

A: "Doubles" indicates geometric growth, which represents an Exponential model.
B: Constant adding rate of "+12 gallons" represents an arithmetic Linear model.

SPED Checkpoint

Use real-life visual analogies: Linear increases like standard stairs; Exponential multiplies like bacteria spreading rapidly.

Question 30

Write Linear Eq

Point: (0, 4) | m = 3

Ans: \( y = 3x + 4 \)

Step-by-Step Solution

1. Form: \( y = mx + b \).
2. Identify y-intercept: \( (0, 4) \rightarrow b = 4 \).
3. Slope \( m = 3 \).
4. Equation: \( \mathbf{y = 3x + 4} \).

SPED Checkpoint

Make sure students place coordinates correctly. They sometimes write \( y = 4x + 3 \) instead, swapping variables \( m \) and \( b \).

UNIT: ALGEBRA 1 REINFORCEMENT KEY PAGE 6 OF 6 ENG-TEACHER-REV.01