Slope Checkup Quiz
Slope Quick Check
Demonstrate mastery of slope types, formulas, graphs, and line verification.
Score _____ / 20 pts
Name:
Date:
Period:
1 The Four Types of Slope
4 Points (1 pt each)
In each coordinate plane, sketch a straight line that represents the specified type of slope.
A. Positive Slope
B. Negative Slope
C. Zero Slope
D. Undefined Slope
2 Slope from Two Points
4 Points (2 pts each)
Use \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Show all substitution and simplify.
A. \((2, 3)\) and \((6, 11)\) Show steps
\(m\) =
B. \((-1, 4)\) and \((3, -4)\) Watch signs
\(m\) =
3 Is the Point on the Line?
4 Points (2 pts each)
Given Equation: \(y = 2x - 3\)
Substitute \((x, y)\) to check if statement is true. Show work and circle answer.
A. Is \((3, 3)\) on the line?
YES NO
B. Is \((-1, -4)\) on the line?
YES NO
4 Read Slope from a Graph
4 Points (2 pts each)
Count rise and run between highlighted lattice points to find \(m\).
Line 1 x y
Rise = ______
Run = ______
\(m\) = ______
Line 2 x y
Rise = ______
Run = ______
\(m\) = ______
5 Graph Line from Point & Slope
4 Points
Given Point: \(P(-2, 1)\)
Given Slope: \(m = \frac{3}{2}\)
Plot point \(P\), use slope to plot at least 2 more points, and draw the line with arrows.
5 -5 5 -5 x y
Plotted Points:
\(P_1\): (-2, 1)
\(P_2\): (____, ____)
\(P_3\): (____, ____)
Algebra 1 • Unit: Linear Relationships & Slope Double-check your negative signs and fraction simplifications!
Slope Checkup Answer Key
Slope Quick Check
Teacher Answer Key
Complete solutions, common student pitfalls, and point-by-point scoring criteria.
Max Score 20 / 20 pts
Q1: 4 pts (1 ea)
Q2: 4 pts (2 ea)
Q3: 4 pts (2 ea)
Q4: 4 pts (2 ea)
Q5: 4 pts (full)
1 The Four Types of Slope (4 pts)
1 pt per accurate sketch
Accept any straight line oriented in the correct direction; arrows optional.
A. Positive Slope \(m > 0\) (Rises)
B. Negative Slope \(m < 0\) (Falls)
C. Zero Slope \(m = 0\) (Horizontal)
D. Undefined Slope \(m = \text{undef}\) (Vertical)
2 Slope from Two Points (4 pts)
1 pt formula, 1 pt answer
Formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Must show correct substitution.
A. \((2, 3)\) and \((6, 11)\) 2 / 2 pts
\(m = \frac{11 - 3}{6 - 2} = \frac{8}{4} = 2\)
(Also accept \(\frac{3 - 11}{2 - 6} = \frac{-8}{-4} = 2\))
\(m\) =
2
B. \((-1, 4)\) and \((3, -4)\) 2 / 2 pts
\(m = \frac{-4 - 4}{3 - (-1)} = \frac{-8}{3 + 1} = \frac{-8}{4} = -2\)
Common Error: subtracting denominator as \(3 - 1 = 2\).
\(m\) =
-2
3 Is Point on Line? (4 pts)
1 pt work, 1 pt decision
Given Equation: \(y = 2x - 3\)
Verify algebraically by substituting \(x\) and \(y\).
A. Is \((3, 3)\) on the line?
YES ✓ NO
Sub \(x = 3, y = 3\): \(3 \stackrel{?}{=} 2(3) - 3 \implies 3 = 6 - 3 = 3\) ✔
Statement is true \(\implies\) Point IS on line.
B. Is \((-1, -4)\) on the line?
YES NO ✓
Sub \(x = -1, y = -4\): \(-4 \stackrel{?}{=} 2(-1) - 3 \implies -4 = -2 - 3 = -5\) ✘
\(-4 \neq -5\) \(\implies\) Point is NOT on line.
4 Read Slope from Graph (4 pts)
2 pts per line
Dashed triangles show Rise and Run counting steps.
Line 1 Solution +2 +3
Rise = +3
Run = +2
\(m\) = \(\frac{3}{2}\) or \(1.5\)
Line 2 Solution +2 -4
Rise = -4 (or -2)
Run = +2 (or +1)
\(m\) = \(-2\)
5 Graph from Point & Slope (4 pts)
1 pt P, 1 pt slope, 2 pts line
Point: \(P(-2, 1)\)
Slope: \(m = \frac{3}{2}\) (Up 3, Right 2)
Check plotted coordinates and straight line with arrows through grid.
5 -5 5 -5 x y P(-2,1) (0,4) (-4,-2)
Plotted Points Key:
\(P_1\): (-2, 1) (given)
\(P_2\): (0, 4)
\(P_3\): (-4, -2)
Algebra 1 • Slope Mastery Scoring Guide Grade scale: 18-20 Mastery (A), 15-17 Proficient (B), 12-14 Developing (C)
