Units Six and Seven Quiz
Eureka Math • Grade 3 Module 3 Checkpoint
Units of 6 and 7 Quiz
Covering Lessons 3, 4, 5, & 7 • Unknowns, Fact Strategies, & Two-Step Problems
Total Score _____ / 25
Name:
Date:
Class:
LESSON 3
Finding Unknowns with Letters
8 Points
- Find the value of the unknown letter in each equation. (1 pt each)
\(p \times 6 = 24\)
\(p =\)
\(42 \div m = 7\)
\(m =\)
\(7 \times c = 49\)
\(c =\)
\(k \div 6 = 8\)
\(k =\)
- Examine the tape diagram below. (4 pts)
Tape Diagram 6 6 6 6 6 6 Total = t
a. Write a multiplication equation with letter \(t\):
b. Write a division equation with letter \(t\):
c. Solve: \(t =\)
LESSON 4
Units of 6: Skip-Counting & Distributive Strategy
7 Points
- Skip-count by sixes to fill in the missing multiples on the number track. (3 pts)
6
12
24
30
42
48
60
- Use the 5s and 1s break-apart strategy to solve \(6 \times 8\). Complete the number bond and equations. (4 pts)
Number Bond 6 eights 5 eights 1 eight
\(6 \times 8 = (5 \times 8) + (1 \times 8)\)
\(6 \times 8 =\) \(+\)
\(6 \times 8 =\)
Eureka Math (2015) • Grade 3 Module 3 Page 1 of 2 Turn page for Section 3 & 4 →
Grade 3 Module 3 Checkpoint • Lessons 5 & 7
Student Name:
LESSON 5
Units of 7: Decomposing Facts (5s & 2s)
5 Points
- Decompose 7 into 5 and 2 to solve \(7 \times 7\). Fill in the number bond and blanks. (3 pts)
Number Bond 7 sevens 5 sevens 2 sevens
\(7 \times 7 = (5 \times 7) + (2 \times 7)\)
\(7 \times 7 =\) \(+\)
\(7 \times 7 =\)
- Compute the following multiplication and division facts. (0.5 pt each = 2 pts)
\(7 \times 4 =\)
\(35 \div 7 =\)
\(7 \times 6 =\)
\(56 \div 7 =\)
LESSON 7
Two-Step Word Problem (Read-Draw-Write)
5 Points
- Maya buys 6 packs of glitter gel pens for her art club. Each pack contains 7 gel pens. During art club, her classmates use 18 of the pens. How many gel pens does Maya have left?
a. DRAW: Create a tape diagram to model the problem. Label the unknown with a letter. (2 pts)
b. WRITE EQUATIONS: Write equations to solve both steps of the problem. (2 pts)
c. WRITE STATEMENT: Write your answer as a complete sentence with units. (1 pt)
Eureka Math (2015) • Grade 3 Module 3 Page 2 of 2 Great job showing your mathematical thinking!
Units Six and Seven Answer Key
Teacher Guide & Key Eureka Math • Grade 3 Module 3
Units of 6 and 7 Quiz — Answer Key
Standards: 3.OA.3, 3.OA.4, 3.OA.5, 3.OA.7, 3.OA.8 • Total: 25 Points
Mastery Standard 20 / 25 (80%)
LESSON 3
Finding Unknowns with Letters — Solutions
8 Points Total
1. Equations with Unknown Letters (1 pt each = 4 pts) Criteria: Correct numerical value
\(p \times 6 = 24\)
\(p = 4\)
Think: \(24 \div 6 = 4\)
\(42 \div m = 7\)
\(m = 6\)
Think: \(42 \div 7 = 6\)
\(7 \times c = 49\)
\(c = 7\)
Square fact: \(7 \times 7\)
\(k \div 6 = 8\)
\(k = 48\)
Think: \(6 \times 8 = 48\)
2. Tape Diagram & Unknown Letter (4 pts) Criteria: Equations & solution
a. Multiplication: \(6 \times 6 = t\) or \(t = 6 \times 6\) (1.5 pts: Must include letter \(t\))
b. Division: \(t \div 6 = 6\) (1.5 pts: Must include letter \(t\))
c. Value of \(t\): \(t = 36\) (1 pt)
LESSON 4
Units of 6: Skip-Counting & Distributive Strategy — Solutions
7 Points Total
3. Skip-Counting Sequence (1 pt per blank = 3 pts) Identifies multiples of 6
6
12
18
24
30
36
42
48
54
60
4. Distributive Property & Number Bond (4 pts) Eureka 5s and 1s decomposition
Decomposition: \(6 \times 8 = (5 \times 8) + (1 \times 8)\)
Step 1 (Partial Products): \(6 \times 8 = \mathbf{40} + \mathbf{8}\) (2 pts: 1 pt for 40, 1 pt for 8)
Step 2 (Final Product): \(6 \times 8 = \mathbf{48}\) (2 pts)
Pedagogical Note: Students leverage the known fact \(5 \times 8 = 40\) and add one more unit of 8 to build conceptual understanding rather than rote memorization.
Eureka Math (2015) • Grade 3 Module 3 Page 1 of 2 See Page 2 for Lessons 5 & 7 and Scoring Rubric →
Answer Key & Rubric • Lessons 5 & 7 Solutions
Scoring Guide & Remediation Notes
LESSON 5
Units of 7: Decomposing Facts (5s & 2s) — Solutions
5 Points Total
5. Distributive Strategy with 7s (3 pts) 5s and 2s break-apart
Decomposition: \(7 \times 7 = (5 \times 7) + (2 \times 7)\)
Step 1 (Addends): \(7 \times 7 = \mathbf{35} + \mathbf{14}\) (1.5 pts: 0.75 pt each)
Step 2 (Final Product): \(7 \times 7 = \mathbf{49}\) (1.5 pts)
