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Pattern Detectives

A 30-minute elementary math lesson where students investigate and articulate arithmetic patterns in multiplication, focusing on factors of 2, 5, 9, 10, and square numbers.

Hhlittlejohn

Pattern Detectives

A 30-minute elementary math lesson where students investigate and articulate arithmetic patterns in multiplication, focusing on factors of 2, 5, 9, 10, and square numbers.

Hhlittlejohn

Rule B: Even × Odd

Example: \(2 \times 7 =\) _____

The product is always:

EVEN ODD

Rule C: Odd × Odd

Example: \(3 \times 5 =\) _____

The product is always:

EVEN ODD

The Imposter Fact: One of these equations has an impossible answer based on the rules. Which one is impossible? Explain why below.

\(6 \times 7 = 42\) \(8 \times 4 = 31\) \(5 \times 9 = 45\)

4 Case File 4: Mystery Number Suspects

Read clues and identify the secret number

Suspect Alpha

  • I am a multiple of 5.
  • I am an even number.
  • I am greater than 30 and less than 50.

Mystery Number:

Suspect Beta

  • I am a multiple of 9.
  • My tens digit is 6.
  • The sum of my two digits is 9.

Mystery Number:

Final Mission: Secret Agent Exit Code

Turn-In Ticket

A rookie agent asks: "Can a number ending in 3 ever be a multiple of 2 or 5?" Use what you learned today to write your detective explanation:

Pattern Detectives Student Worksheet • Page 2 of 2 Operations & Algebraic Thinking • 3.OA.D.9

The product is always:

EVEN ✓ ODD

Rule B: Even × Odd

Ex: \(2 \times 7 =\) 14

The product is always:

EVEN ✓ ODD

Rule C: Odd × Odd

Ex: \(3 \times 5 =\) 15

The product is always:

EVEN ODD ✓

The Imposter Fact Solution:

The imposter is \(8 \times 4 = 31\)! Explanation: Both 8 and 4 are even numbers, so their product must be even. 31 is odd (the correct product is 32).

4 Case File 4: Mystery Number Suspects • Solutions

Deductive Reasoning

Suspect Alpha Solution

  • Multiples of 5 between 30 and 50: 35, 40, 45.
  • Must be even: only 40 ends in 0.

Mystery Number: 40

Suspect Beta Solution

  • Tens digit is 6 (number is in the 60s).
  • Digits sum to 9: \(6 + 3 = 9\). Multiples of 9: \(9 \times 7 = 63\).

Mystery Number: 63

Final Mission Exit Code: Model Explanation & Rubric

Exemplar

Answer: NO.
Model Student Rationale: "A number ending in 3 can never be a multiple of 2 or 5. All multiples of 2 are even numbers and must end in 0, 2, 4, 6, or 8 (3 is odd). All multiples of 5 must end in either 0 or 5. Since 3 is neither 0 nor 5, it cannot be in the 5s family."

Scoring Criteria: 2 pts = Correct "No" with explanations for both 2s (even) and 5s (ends in 0/5); 1 pt = Correct answer with partial reason; 0 pts = Incorrect or guessing.

Pattern Detectives Answer Key • Page 2 of 2 Operations & Algebraic Thinking • 3.OA.D.9

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