Fraction Feasts

Mastery Level

4

Computation Fluency

Find the common denominator, show your work, and write answers in simplest form (or mixed numbers):

Problem 4 \( \frac{5}{12} + \frac{1}{4} \)

Answer:

Problem 5 \( \frac{2}{3} + \frac{4}{9} \)

Answer (Mixed):

Problem 6 \( \frac{3}{7} + \frac{1}{2} \)

Answer:

Problem 7 \( \frac{5}{8} + \frac{1}{6} \)

Answer:

5

Bistro Application Problems

Artisan Sourdough Blend

Baker Marco mixes \( \frac{3}{5} \) kg of rye flour and \( \frac{1}{4} \) kg of spelt flour into a mixing bowl. What is the total mass of flour used in the batch?

Total Mass:

kg

Fruit Parfait Layering

Pastry Chef Nina uses \( \frac{2}{3} \) cup of blueberry coulis and \( \frac{3}{4} \) cup of vanilla cream. She says the bowl holds more than \( 1 \frac{1}{3} \) cups. Is she correct?

Circle one:   YES  /  NO Total =   cups

Sous-Chef Error Analysis

Critique & Correct

Apprentice Chef Chloe calculated: \( \frac{2}{5} + \frac{1}{3} = \frac{2+1}{5+3} = \frac{3}{8} \). Explain Chloe's mistake and write the correct calculation.

Her conceptual mistake:

Correct solution:

Just like you cannot count "2 halves and 1 third" as "3 items of equal value," fractions cannot be summed without a common denominator because the denominator dictates unit size. The common denominator re-slices both quantities into identical units.

Worksheet & Exit Ticket Solutions

Quick scoring reference, answer keys, and targeted student remediation prompts.

Complete Keys

Fraction Kitchen Worksheet Solutions

Parts 1, 2, & 3

1B. LCD(3, 5) = 15

1C. LCD(8, 12) = 24

2A. \( \frac{1}{2} \times \frac{4}{4} = \mathbf{\frac{4}{8}} \)

2B. \( \frac{2}{3} \times \frac{4}{4} = \mathbf{\frac{8}{12}} \)

Prob 1. \( \frac{1}{4} + \frac{2}{3} = \frac{3}{12} + \frac{8}{12} = \mathbf{\frac{11}{12}} \)

Prob 2. \( \frac{3}{8} + \frac{1}{2} = \frac{3}{8} + \frac{4}{8} = \mathbf{\frac{7}{8}} \)

Prob 3. \( \frac{2}{5} + \frac{3}{10} = \frac{4}{10} + \frac{3}{10} = \frac{7}{10} \)

Parts 4, 5, & 6

Prob 4. \( \frac{5}{12} + \frac{1}{4} = \frac{5}{12} + \frac{3}{12} = \frac{8}{12} = \mathbf{\frac{2}{3}} \)

Prob 5. \( \frac{2}{3} + \frac{4}{9} = \frac{6}{9} + \frac{4}{9} = \frac{10}{9} = \mathbf{1 \frac{1}{9}} \)

Prob 6. \( \frac{3}{7} + \frac{1}{2} = \frac{6}{14} + \frac{7}{14} = \mathbf{\frac{13}{14}} \)

Prob 7. \( \frac{5}{8} + \frac{1}{6} = \frac{15}{24} + \frac{4}{24} = \mathbf{\frac{19}{24}} \)

Word A. \( \frac{3}{5} + \frac{1}{4} = \frac{12}{20} + \frac{5}{20} = \mathbf{\frac{17}{20}}\text{ kg} \)

Word B. \( \frac{2}{3} + \frac{3}{4} = \frac{8}{12} + \frac{9}{12} = \frac{17}{12} = \mathbf{1 \frac{5}{12}}\text{ cups} \). Nina is YES correct, as \( 1\frac{5}{12} > 1\frac{4}{12} \) (\( 1\frac{1}{3} \)).

Part 6 (Error). Chloe added numerators and denominators. Correct: LCD = 15; \( \frac{6}{15} + \frac{5}{15} = \mathbf{\frac{11}{15}} \).

Chef Check: Exit Ticket Master Key

Total: 3 Points

Q1. LCD Finding

LCD = 12

Accept 24 with note that 12 is the least common multiple.

Q2. Equivalent Fractions

\( \frac{3}{4} = \mathbf{\frac{9}{12}} \)
\( \frac{1}{6} = \mathbf{\frac{2}{12}} \)

Both fractions must share denominator 12.

Q3. Sum & Total

\( \frac{9}{12} + \frac{2}{12} = \mathbf{\frac{11}{12}} \)

Already in simplest form (11 is prime).

Common Student Roadblocks & Rapid Interventions

Roadblock A: Multiplying Denominators without Checking LCD: Students multiply \( 4 \times 6 = 24 \) instead of using 12. Clarify that 24 works as a common denominator, but using the LCM (12) keeps numbers smaller and reduces late simplifying errors.

Roadblock B: Changing Denominators but Not Numerators: Students write \( \frac{1}{4} \rightarrow \frac{1}{12} \). Revisit the area model: cutting each fourth into 3 slices multiplies the number of pieces by 3 as well!