Cyber Grid Slides
Cyber Grid
Defense Initiative
System Status: Critical // Standby for Briefing
MISSION BRIEFING
The Situation
The city's main power grid is under a massive surge. To prevent a total blackout, we need Grid Operators to balance loads and calculate network resistance.
Your Task
Complete five sectors of the grid. Each sector requires precise physics calculations to bypass the security lock.
- Sector 1: Basic Relays
- Sector 2: Real Batteries
- Sector 3: Thermal Recovery
- Sector 4: Resource Billing
- Sector 5: Mesh Nodes
Sector 1
The Basic Relay
ENCRYPTION: LOW
A high-speed server draws 4.5 A from a 120 V line.
1.1 Calculate total power consumption (Watts).
!! CODE FRAGMENT 1 !!
The server's internal resistance must be verified.
1.2 Determine the resistance of the circuit.
If the voltage drops to 105 V but the resistance stays the same...
1.3 Calculate the NEW power output.
Hint: Use \(P = V^2 / R\)
Sector 2
The Battery Lab
ε = 24.0 V
r = 0.50 Ω
The backup battery is connected to an external load of 5.5 Ω.
Code Fragment 2
2.1 Find the total current in the circuit.
System Diagnostic
2.2 Find the terminal voltage.
System Alert: How much power is "lost" as heat inside the battery? (Part 2.3)
Sector 3
Thermal Recovery
An electric heater motor is rated at 1500 W. However, it only performs 1200 J of useful work every second.
3.1 Calculate the efficiency of the motor (%)
!! CODE FRAGMENT 3 !!
3.2 Energy dissipated as heat in 5 minutes?
Formula Bank
Eff = \(\frac{P_{out}}{P_{in}} \times 100\)
Energy = \(P \times t\)
\(P_{heat} = P_{in} - P_{useful}\)
"Energy is never lost, only transformed..."
Sector 4
Resource Billing
The Defense Center monitors use 800 W of power and operate 24 hours a day.
Usage Stats
4.1 Energy used per day in kWh.
!! CODE FRAGMENT 4 !!
4.2 Cost to run for a 30-day month at $0.15/kWh.
Operator Warning
Convert Watts to kiloWatts first!
(1 kW = 1000 W)
Encryption Key 4.3:
Joules in 1 hour?
Sector 5
Mesh Network Nodes
Route Alpha SERIES
Two server clusters with 40 Ω and 60 Ω are connected in series.
5.1 Calculate the total Req.
!! CODE FRAGMENT 5 !!
\(R_{series} = R_1 + R_2\)
Route Beta PARALLEL
Two nodes (20 Ω each) are in parallel to a 120 V source.
5.2 Equivalent Resistance of Beta?
5.3 Total Current from source?
\(\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}\)
Grid Lockdown
To finalize the reboot, sum fragments 1.1, 2.1, 3.1, 4.1, and 5.1.
Multiply the result by 10 to find the code.
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Awaiting final sequence...
Cyber Grid Logbook Worksheet
Cyber Grid Defense
Status: Official Technical Log // Clearance: Level 2
Operator:
Date:
Operational Directive: Solve technical failures in all 5 sectors. Show all work for system verification. The Master Override Code is the sum of results from 1.1, 2.1, 3.1, 4.1, and 5.1, multiplied by 10.
Sector 1: Basic Relays
1.1 Power Consumption (P = VI)
!! CODE FRAGMENT 1 !! : ________ W
1.2 Resistance (R = V/I)
________ Ω
1.3 Power @ 105V
________ W
Sector 2: Battery Lab
2.1 Total Current (\(I = \frac{\epsilon}{R+r}\))
!! CODE FRAGMENT 2 !! : ________ A
2.2 Terminal Voltage
________ V
2.3 Internal Heat Loss
________ W
Sector 3: Thermal Recovery
3.1 Efficiency Rating (%)
!! CODE FRAGMENT 3 !! : ________ %
3.2 Energy Dissipated (J) in 5 min
________ J
Sector 4: Resource Billing
4.1 Daily Energy Usage (kWh)
!! CODE FRAGMENT 4 !! : ________ kWh
4.2 Monthly Operational Cost ($)
$ ________
Sector 5: Mesh Network Nodes
5.1 Alpha Req (Series)
!! CODE FRAGMENT 5 !! : ________ Ω
5.2 Beta Req (Parallel)
________ Ω
5.3 Beta Total Current (I)
________ A
Master Override Code
Protocol: (F1.1 + F2.1 + F3.1 + F4.1 + F5.1) × 10
Cyber Grid Admin Manual Teacher Guide
Admin Manual
Cyber Grid Defense Initiative // Facilitator Guide
CODE: 7432
MISSION PARAMETERS
Gameplay Loop
- 1. Display Sector slide. Students work in teams.
- 2. Teams record work in Technical Logbook.
- 3. Verify Fragment answers before moving to next Sector.
- 4. Final Override: Sum all 5 Fragments and multiply by 10.
Target Objectives
Ohm's Law Internal Resistance Efficiency kWh/Cost Series/Parallel Req
Common Pitfall: Students often forget to convert Watts to kiloWatts in Sector 4.
TECHNICAL SOLUTIONS
Sector 1: Basic Relays
1.1 (Fragment): \(120 \times 4.5 = \mathbf{540 \text{ W}}\)
1.2: \(120 / 4.5 = \mathbf{26.67 \Omega}\)
1.3: \(105^2 / 26.67 = \mathbf{413.38 \text{ W}}\)
Sector 2: Battery Lab
2.1 (Fragment): \(24 / (5.5 + 0.5) = \mathbf{4.0 \text{ A}}\)
2.2: \(24 - (4 \times 0.5) = \mathbf{22.0 \text{ V}}\)
2.3: \(4^2 \times 0.5 = \mathbf{8.0 \text{ W}}\)
Sector 3: Thermal Recovery
3.1 (Fragment): \(1200 / 1500 \times 100 = \mathbf{80\%}\)
3.2: \(P_{loss}=300\text{W}\). \(300 \times 300\text{s} = \mathbf{90,000 \text{ J}}\)
Sector 4: Resource Billing
4.1 (Fragment): \(0.8\text{kW} \times 24\text{h} = \mathbf{19.2 \text{ kWh}}\)
4.2: \(19.2 \times 30 \times \$0.15 = \mathbf{\$86.40}\)
Sector 5: Mesh Network Nodes
5.1 (Fragment): \(40 + 60 = \mathbf{100 \Omega}\)
5.2: \(1/R = 1/20 + 1/20 \Rightarrow \mathbf{10 \Omega}\)
5.3: \(120 / 10 = \mathbf{12 \text{ A}}\)
Master Code Verification
F 1.1 540
F 2.1 4.0
F 3.1 80
F 4.1 19.2
F 5.1 100
=
743.2
Final Protocol
743.2 × 10 = 7432
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